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An equation was used to predict possible sales of phones for 6 months. The actual sales of phones are also listed. Actual sales 55 150 325 510 780 990 Predicted sales 40 150 300 500 800 1,000 The sum of the residuals is ______. Numerical Answers Expected! Answer for Blank 1:
20 is what i put for sum
So residual I think is the difference between the actual and the predicted right?
yes ma'am and then they are asking for the sum after you do each one :)
well then I believe that answer will be given by this then \[(55+150+325+510+780+990)-(40+150+300+500+800+1000)\]
which does come out to be 20
thats now how i did it
i subtracted each actual sale and predicted then found the answer to them and added them all together :)
that is the same thing
just written differently remember addition is commutative
ok may you make sure another is correct?
or a couple? :D
is it something about residuals or whatever?
algebra still lol
can you still help????
I'm waiting I said I might be able to help
I have to get a look of the warlock before I know Iike residuals was kind of a new term for me
The following data show the scores Gina obtained on 12 IQ tests: 93, 83, 74, 74, 83, 92, 93, 94, 90, 87, 83, 86 The box plot below represents the data: box plot has minimum value equal to 74, lower quartile equal to 83, median equal to 86.5, upper quartile equal to 89 and maximum value equal to 94 Which of the following is shown incorrectly in the box plot? Median Lower quartile Upper quartile Maximum value
well looking at the data have you tried to find the information yet?
like first thing is to order the data from least to greatest
i think its c
I like to use a stem leaf chart to organize my data
ok what is that?
we see from the chart 74 is indeed the min and 94 is the max
the median is the number in the middle of the data we have an even amount amount of data points so we will need to look at the two middle numbers and find the average of two middle numbers to find the median
so what two numbers are in the middle of all that junk there
I will give a hint look at 12/2 and (12/2)+1 entries that is looked at the 6th and 7th entry
2 and 3?
|dw:1435972025373:dw| 1st entry=74 2nd entry=74 3rd entry=83 4th entry=83 5th entry=83 6th entry=86 7th entry=87 8th entry=90 9th entry=92 10th entry=93 11th entry=93 12th entry=94
|dw:1435972118924:dw| to find the median we need to find the average of 86 and 87
how do you do that again?
the average of n numbers is the sum of those n numbers divided by the number of numbers n
? can u show me?
that is to find the average of two numbers, 86 and 87 you add them and divide by the number of numbers, 2
are you good with the median?
do you need help adding 86 and 87 and dividing that result by 2?
I will give you a hint what number is midway between 86 and 87
if you don't know then just do (86+87)/2
anyways after we find the median we will find the "median" of the upper data and find the "median" of the lower data I put median in quotation marks since we are actually finding the upper quartile and lower quartile number respectively
right this is correctly shown as the median on the graph
so moving on to upper quartile number
the median split the data up in two halves
we want to find the middle number in each
90,92,93,93,94 what number is the middle number here
right that number is the upper quartile number and yes 93 is in the middle there because you have exactly two entries to the right and left of it and we can end the discussion here since that is not shown in the graph correctly we need to spot the middle number in the lower data points 74,74,83,83,83 83 is the lower quartile number since it is the middle number of the lower points you have exactly two entries to right and left of it that is shown correctly in the graph
|dw:1435972933122:dw| the graph should have looked something like this
badly drawn but I the marks above and the box you see is lying at the correct numbers
ok so the answer is c? "upper quartile"