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help_people

  • one year ago

HELP TO MAKE SURE WORK IS CORRECT PLEASE!!!

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  1. help_people
    • one year ago
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    An equation was used to predict possible sales of phones for 6 months. The actual sales of phones are also listed. Actual sales 55 150 325 510 780 990 Predicted sales 40 150 300 500 800 1,000 The sum of the residuals is ______. Numerical Answers Expected! Answer for Blank 1:

  2. help_people
    • one year ago
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    20 is what i put for sum

  3. freckles
    • one year ago
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    So residual I think is the difference between the actual and the predicted right?

  4. help_people
    • one year ago
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    yes ma'am and then they are asking for the sum after you do each one :)

  5. freckles
    • one year ago
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    well then I believe that answer will be given by this then \[(55+150+325+510+780+990)-(40+150+300+500+800+1000)\]

  6. freckles
    • one year ago
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    which does come out to be 20

  7. help_people
    • one year ago
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    thats now how i did it

  8. help_people
    • one year ago
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    i subtracted each actual sale and predicted then found the answer to them and added them all together :)

  9. freckles
    • one year ago
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    that is the same thing

  10. freckles
    • one year ago
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    just written differently remember addition is commutative

  11. help_people
    • one year ago
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    ok may you make sure another is correct?

  12. help_people
    • one year ago
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    or a couple? :D

  13. freckles
    • one year ago
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    maybe

  14. freckles
    • one year ago
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    is it something about residuals or whatever?

  15. help_people
    • one year ago
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    no

  16. help_people
    • one year ago
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    algebra still lol

  17. help_people
    • one year ago
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    can you still help????

  18. freckles
    • one year ago
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    I'm waiting I said I might be able to help

  19. freckles
    • one year ago
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    I have to get a look of the warlock before I know Iike residuals was kind of a new term for me

  20. help_people
    • one year ago
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    ok

  21. help_people
    • one year ago
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    The following data show the scores Gina obtained on 12 IQ tests: 93, 83, 74, 74, 83, 92, 93, 94, 90, 87, 83, 86 The box plot below represents the data: box plot has minimum value equal to 74, lower quartile equal to 83, median equal to 86.5, upper quartile equal to 89 and maximum value equal to 94 Which of the following is shown incorrectly in the box plot? Median Lower quartile Upper quartile Maximum value

  22. help_people
    • one year ago
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  23. freckles
    • one year ago
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    well looking at the data have you tried to find the information yet?

  24. freckles
    • one year ago
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    like first thing is to order the data from least to greatest

  25. help_people
    • one year ago
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    i think its c

  26. freckles
    • one year ago
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    I like to use a stem leaf chart to organize my data

  27. help_people
    • one year ago
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    ok what is that?

  28. freckles
    • one year ago
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    |dw:1435971696968:dw|

  29. freckles
    • one year ago
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    we see from the chart 74 is indeed the min and 94 is the max

  30. freckles
    • one year ago
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    |dw:1435971803890:dw|

  31. help_people
    • one year ago
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    yeah

  32. freckles
    • one year ago
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    the median is the number in the middle of the data we have an even amount amount of data points so we will need to look at the two middle numbers and find the average of two middle numbers to find the median

  33. freckles
    • one year ago
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    so what two numbers are in the middle of all that junk there

  34. freckles
    • one year ago
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    I will give a hint look at 12/2 and (12/2)+1 entries that is looked at the 6th and 7th entry

  35. help_people
    • one year ago
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    2 and 3?

  36. freckles
    • one year ago
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    |dw:1435972025373:dw| 1st entry=74 2nd entry=74 3rd entry=83 4th entry=83 5th entry=83 6th entry=86 7th entry=87 8th entry=90 9th entry=92 10th entry=93 11th entry=93 12th entry=94

  37. freckles
    • one year ago
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    |dw:1435972118924:dw| to find the median we need to find the average of 86 and 87

  38. help_people
    • one year ago
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    ok

  39. help_people
    • one year ago
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    how do you do that again?

  40. freckles
    • one year ago
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    the average of n numbers is the sum of those n numbers divided by the number of numbers n

  41. help_people
    • one year ago
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    ? can u show me?

  42. freckles
    • one year ago
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    that is to find the average of two numbers, 86 and 87 you add them and divide by the number of numbers, 2

  43. freckles
    • one year ago
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    are you good with the median?

  44. freckles
    • one year ago
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    do you need help adding 86 and 87 and dividing that result by 2?

  45. freckles
    • one year ago
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    I will give you a hint what number is midway between 86 and 87

  46. freckles
    • one year ago
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    if you don't know then just do (86+87)/2

  47. freckles
    • one year ago
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    anyways after we find the median we will find the "median" of the upper data and find the "median" of the lower data I put median in quotation marks since we are actually finding the upper quartile and lower quartile number respectively

  48. help_people
    • one year ago
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    86.5

  49. freckles
    • one year ago
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    right this is correctly shown as the median on the graph

  50. freckles
    • one year ago
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    so moving on to upper quartile number

  51. freckles
    • one year ago
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    the median split the data up in two halves

  52. freckles
    • one year ago
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    we want to find the middle number in each

  53. freckles
    • one year ago
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    90,92,93,93,94 what number is the middle number here

  54. help_people
    • one year ago
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    93

  55. freckles
    • one year ago
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    right that number is the upper quartile number and yes 93 is in the middle there because you have exactly two entries to the right and left of it and we can end the discussion here since that is not shown in the graph correctly we need to spot the middle number in the lower data points 74,74,83,83,83 83 is the lower quartile number since it is the middle number of the lower points you have exactly two entries to right and left of it that is shown correctly in the graph

  56. help_people
    • one year ago
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    ok

  57. freckles
    • one year ago
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    |dw:1435972933122:dw| the graph should have looked something like this

  58. freckles
    • one year ago
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    badly drawn but I the marks above and the box you see is lying at the correct numbers

  59. help_people
    • one year ago
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    ok so the answer is c? "upper quartile"

  60. help_people
    • one year ago
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    @freckles ^

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