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anonymous

  • one year ago

y = −x^2 + 4 y = 2x + 1 How would you solve by elimination or substitution?

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  1. rvc
    • one year ago
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    we have : \[\rm y=-x^2+4~ and ~y=2x+1\]

  2. anonymous
    • one year ago
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    yes, I don't get how you would solve them though

  3. rvc
    • one year ago
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    so we have two values for y

  4. rvc
    • one year ago
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    we can put any of those

  5. anonymous
    • one year ago
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    like \[-x^2+4=2x+1\]

  6. rvc
    • one year ago
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    yes

  7. rvc
    • one year ago
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    now solve further :)

  8. anonymous
    • one year ago
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    but how would you subract them. Thats what im stuck on.

  9. rvc
    • one year ago
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    here it is : \[\rm 2x+1+x^2-4\]

  10. anonymous
    • one year ago
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    that is what y equals then right?

  11. rvc
    • one year ago
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    no since when we solve the equation we are left only with x. then we will put the value of x in any one of the original equation to find the value of y

  12. anonymous
    • one year ago
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    Im really stuck then .. how would you find what x and y are?

  13. rvc
    • one year ago
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    here it is : \[\sf x^2+2x-3=0\]

  14. rvc
    • one year ago
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    we have to solve the quadratic equation

  15. anonymous
    • one year ago
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    I get x = 1, -3

  16. rvc
    • one year ago
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    yep now put one value at a time in either : y = 2x+1 or y=-x^2+4

  17. anonymous
    • one year ago
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    Thank you :)

  18. rvc
    • one year ago
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    Thank you All the best :)

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