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anonymous
 one year ago
@rvc
anonymous
 one year ago
@rvc

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got the answer for a and b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part a.) is OC = OT  CT = R r

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part b.) is R*sin*theta = r(1+ sin theta)

rvc
 one year ago
Best ResponseYou've already chosen the best response.0im extremely sorry gtg now

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3we can write this: \[\Large \begin{gathered} 21 = 2R + R2\theta = 2R + 2R\arcsin \left( {\frac{3}{4}} \right) = \hfill \\ \hfill \\ = 2R\left\{ {1 + \arcsin \left( {\frac{3}{4}} \right)} \right\} \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3since: \[\Large ATB = R2\theta \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea I did that but my problem is why am I to taking the 1 with the given angle?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3by definition of radians, we have: \[\Large L = \alpha R\] dw:1436029827922:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 your answer is wrong =_=

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino I do remember that arc length formula but what I'm asking is that, if we are given that O is sin theta = 3/4 why are we taking the 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino what you've written in your answer is exactly the same thing that is written in the solution bank I simply wanna know why you talking (1 + arcsin(3/4) instead of just arcsin3/4?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3since I have factored out the quantity 2R

dan815
 one year ago
Best ResponseYou've already chosen the best response.0hey michele can you tell me what's wrong in my method, i cant find it

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3your link tells me "500 Internal Server Error" @dan815

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhhhh Ok I got it!!

dan815
 one year ago
Best ResponseYou've already chosen the best response.0oh oops its the whole perimeter not just the arc perimeter

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0THANK YOU @Michele_Laino! :DDDDD

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3yes! the perimeter is the perimeter of the sector @dan815

dan815
 one year ago
Best ResponseYou've already chosen the best response.0http://prntscr.com/7orzms hehe too clumpsy
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