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I need your help :/
i need medals
  • rvc
yes @nopen

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Other answers:

it's part c
I got the answer for a and b
Part a.) is OC = OT - CT = R- r
Part b.) is R*sin*theta = r(1+ sin theta)
  • rvc
im extremely sorry gtg now
we can write this: \[\Large \begin{gathered} 21 = 2R + R2\theta = 2R + 2R\arcsin \left( {\frac{3}{4}} \right) = \hfill \\ \hfill \\ = 2R\left\{ {1 + \arcsin \left( {\frac{3}{4}} \right)} \right\} \hfill \\ \end{gathered} \]
since: \[\Large ATB = R2\theta \]
yea I did that but my problem is why am I to taking the 1 with the given angle?
by definition of radians, we have: \[\Large L = \alpha R\] |dw:1436029827922:dw|
http://prntscr.com/7orri3
@dan815 your answer is wrong =_=
@Michele_Laino I do remember that arc length formula but what I'm asking is that, if we are given that O is sin theta = 3/4 why are we taking the 1?
what is the answer
2.43
@Michele_Laino what you've written in your answer is exactly the same thing that is written in the solution bank I simply wanna know why you talking (1 + arcsin(3/4) instead of just arcsin3/4?
*are taking
since I have factored out the quantity 2R
hey michele can you tell me what's wrong in my method, i cant find it
your link tells me "500 Internal Server Error" @dan815
lol
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how about that one
Ohhhhh Ok I got it!!
oh oops its the whole perimeter not just the arc perimeter
THANK YOU @Michele_Laino! :DDDDD
yes! the perimeter is the perimeter of the sector @dan815
http://prntscr.com/7orzms hehe too clumpsy

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