## anonymous one year ago @rvc

1. anonymous

2. anonymous

i need medals

3. rvc

yes @nopen

4. anonymous

it's part c

5. anonymous

I got the answer for a and b

6. anonymous

Part a.) is OC = OT - CT = R- r

7. anonymous

Part b.) is R*sin*theta = r(1+ sin theta)

8. rvc

im extremely sorry gtg now

9. Michele_Laino

we can write this: $\Large \begin{gathered} 21 = 2R + R2\theta = 2R + 2R\arcsin \left( {\frac{3}{4}} \right) = \hfill \\ \hfill \\ = 2R\left\{ {1 + \arcsin \left( {\frac{3}{4}} \right)} \right\} \hfill \\ \end{gathered}$

10. Michele_Laino

since: $\Large ATB = R2\theta$

11. anonymous

yea I did that but my problem is why am I to taking the 1 with the given angle?

12. Michele_Laino

by definition of radians, we have: $\Large L = \alpha R$ |dw:1436029827922:dw|

13. dan815
14. anonymous

15. anonymous

@Michele_Laino I do remember that arc length formula but what I'm asking is that, if we are given that O is sin theta = 3/4 why are we taking the 1?

16. dan815

17. anonymous

2.43

18. anonymous

@Michele_Laino what you've written in your answer is exactly the same thing that is written in the solution bank I simply wanna know why you talking (1 + arcsin(3/4) instead of just arcsin3/4?

19. anonymous

*are taking

20. Michele_Laino

since I have factored out the quantity 2R

21. dan815

hey michele can you tell me what's wrong in my method, i cant find it

22. Michele_Laino

23. anonymous

lol

24. dan815

25. dan815

26. anonymous

Ohhhhh Ok I got it!!

27. dan815

oh oops its the whole perimeter not just the arc perimeter

28. anonymous

THANK YOU @Michele_Laino! :DDDDD

29. Michele_Laino

yes! the perimeter is the perimeter of the sector @dan815

30. Michele_Laino

:) @nopen

31. dan815

http://prntscr.com/7orzms hehe too clumpsy