Carl conducted an experiment to determine if there is a difference in the mean body temperature between men and women. He found that the mean body temperature for a sample of 100 men was 91.1 with a population standard deviation of 0.52 and the mean body temperature for a sample of 100 women was 97.6 with a population standard deviation of 0.45.
Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women.
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Using complete sentences, explain what these confidence intervals mean in the context of the problem.
x-bar = 91.1
ME = 2.3263*0.52 = 1.210
98% CI:: 91.1-1.21 < u < 91.1+1.21
98% CI: 89.89 < u < 92.31
x-bar = 97.6
ME = 2.3263*0.45 = 1.05
98% CI: 97.6-1.05 < u < 97.6+1.05
98% CI: 96.55 < u < 98.65
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"He found that the mean body temperature for a sample of 100 men was 91.1 with a population standard deviation of 0.52 and the mean body temperature for a sample of 100 women was 97.6 with a population standard deviation of 0.45."
and could u explain the variables again plz
100 men was 91.1, deviation was 0.52, and mean sample was 100 women