anonymous
  • anonymous
Velocity Magnitude If a jet is traveling 200 mi/hr and the tail wind is 40 mi/hour what is the resulting velocity? I think it is 200+ 40 = 240 magnitude And is its counter clockwise 240 degrees too? Am I correct?
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
If it is 240 it is going South West?
anonymous
  • anonymous
I think the magnitude is 240, but there's no info that allows you to figure out the angle
anonymous
  • anonymous
East = 0 degree

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anonymous
  • anonymous
ok. then the angle would be 0°
anonymous
  • anonymous
because both the plane and the wind are east
anonymous
  • anonymous
This is what it states. The direction of a vector is often expressed as a counter clockwise angle of rotation of the vector from due east. In such a convention, East is 0 degree, North 90, West is 180 and south 270.
anonymous
  • anonymous
I have to find the Magnitude and the direction
anonymous
  • anonymous
oh, gotcha. I thought you were saying that the plane was traveling east. Whatever direction the plane is flying in is the angle because a tail wind by definition is in the direction of travel. |dw:1436033950387:dw| they have to tell you a direction to start with
anonymous
  • anonymous
Ok, so we are staring with East 0 degree right?
anonymous
  • anonymous
they really gave you speeds and asked you to find velocity
anonymous
  • anonymous
Since we have 240 mag, which is a 45 degree we would be going in the direction of north east?
anonymous
  • anonymous
Honestly, I don't see how you can get a direction from the information provided. I just put that up there as an example of 2 different directions having the same magnitude
anonymous
  • anonymous
Is there maybe a picture with this problem?
anonymous
  • anonymous
Nope, just shows the jet and the wind magnitude
anonymous
  • anonymous
Maybe the jet is going east?
anonymous
  • anonymous
I'd go with that. really you could go with any direction.
anonymous
  • anonymous
I do have to calculate for Side Wind on the next problem, which will push it at a different angle
anonymous
  • anonymous
ok. that kind of makes sense. as if it's going 0° initially and then the side wind pushes it in another direction
anonymous
  • anonymous
still they could have made it more clear by stating explicitly that the direction was due east
anonymous
  • anonymous
I have to calculate for Tail, Head and Side Wind... Tail shoud be 240 and Head should be 160 and I have to do the side, which the wind is coming from the north so it will push it South east
anonymous
  • anonymous
yes
anonymous
  • anonymous
so your angle for the head wind was also 0°?
anonymous
  • anonymous
Yes, because it is just pushing toward the jet
anonymous
  • anonymous
ok
anonymous
  • anonymous
The side wind is the only thing I see that would make it change from east.
anonymous
  • anonymous
yes it is
anonymous
  • anonymous
Is the side wind also 40 mph ?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Yeah it must be east. It tells us here The direction of a vector is often expressed as a counter clockwise angle of rotation of the vector from due east. In such a convention, East is 0 degree, North 90, West is 180 and south 270
anonymous
  • anonymous
Hummm or is it West????
anonymous
  • anonymous
Is it going from East to West so the Plane is moving West?
anonymous
  • anonymous
I'd stick with east. it really doesn't say and east is a reasonable guess since that's 0
anonymous
  • anonymous
Yeah but it would move at 180 degree since it is moving at a straight line
anonymous
  • anonymous
which 180 would be moving West
anonymous
  • anonymous
that's kind of what I'm saying. they didn't give you and explicit direction to begin with. When you work a vector problem, it's supposed to say for example 40 mph due east, or 200 mph at 45° SE. They only gave you the magnitudes of the vectors. There's no way for you to figure out the directions. You just have to pick a assume as the starting point and work the rest of the problem with that assumed direction. Picking 0° is just the easiest starting directions
anonymous
  • anonymous
0 degree is the starting and they stat it is east so if the jet moves with only tail or head wind, it moves at 180 degrees
anonymous
  • anonymous
I am assuming this from this passage The direction of a vector is often expressed as a counter clockwise angle of rotation of the vector from due east. In such a convention, East is 0 degree, North 90, West is 180 and south 270
anonymous
  • anonymous
i see what you're saying. let me draw it out
anonymous
  • anonymous
|dw:1436035727364:dw|
anonymous
  • anonymous
they're both still going to be at 0° because the speed of the plane is greater than both the wind's vectors
anonymous
  • anonymous
But if it starts at 0, which it states it is often express as counter clockwise, so a jet moving straight from 0 would be 180
anonymous
  • anonymous
0° /due east is the horizontal x-axis. The angles are expressed starting in the counter clockwise direction
anonymous
  • anonymous
|dw:1436036333325:dw|
anonymous
  • anonymous
So you would say East. Why they make it so confusing lol
anonymous
  • anonymous
yeah I would. I don't know, this is just a really badly worded question
anonymous
  • anonymous
What gets me is where it stats from due east like if you are coming from and then going to
anonymous
  • anonymous
I always think of the start point as the origin, which makes it a little easier
anonymous
  • anonymous
I gotta run. hopefully I was able to give some help. For the sidewind, since it's coming from the north, it will be at a 270° direction
anonymous
  • anonymous
Yes, you are always a lot of help
anonymous
  • anonymous
Thank you!!!
anonymous
  • anonymous
you're welcome |dw:1436036875395:dw|
anonymous
  • anonymous
Thanks!!!

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