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anonymous

  • one year ago

Simplify completely quantity 8 x minus 16 over quantity x squared minus 13 x plus 22 and find the restrictions on the variable.

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    \[\huge\frac{8x-16}{x^2-13x+22}\]?

  3. anonymous
    • one year ago
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    I got x-5/x+1 as my answer but I don't know what the restriction would be

  4. misty1212
    • one year ago
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    did you factor the denomiantor?

  5. anonymous
    • one year ago
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    yes

  6. anonymous
    • one year ago
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    Sorry I meant 8/x-11

  7. misty1212
    • one year ago
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    \[x^2-13x+22=(x-2)(x-11)\]

  8. triciaal
    • one year ago
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    factor the denominator again hint 2*11 = 22 and 2 + 11 = 13

  9. misty1212
    • one year ago
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    then cancel and you get what you wrote

  10. anonymous
    • one year ago
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    But what would be the restrictions?

  11. misty1212
    • one year ago
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    so your answer is correct as for the "restrictions" the denominator cannot be zero

  12. misty1212
    • one year ago
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    \[(x-2)(x-11)=0\\ x=2,x=11\]

  13. misty1212
    • one year ago
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    so the restrictions are \(x\neq2\) and \(x\neq 11\) because if \(x\) where either of those two numbers, the denominator would be zero, and if you try to divide by zero you will explode

  14. anonymous
    • one year ago
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    Ok. I need to ask another one

  15. anonymous
    • one year ago
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    Simplify completely quantity x squared plus 4 x minus 45 all over x squared plus 10 x plus 9 and find the restrictions on the variable.

  16. misty1212
    • one year ago
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    lol the equation tool below is very useful

  17. anonymous
    • one year ago
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    I got x-5/x+1

  18. anonymous
    • one year ago
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    Sorry

  19. misty1212
    • one year ago
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    \[\huge \frac{x^2+4x-45}{x^2+10x+9}\]

  20. misty1212
    • one year ago
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    your answer is correct

  21. anonymous
    • one year ago
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    yes:) What would be the restrictions for this one? My answer is x-5/x+1

  22. misty1212
    • one year ago
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    repeat as before take the denominator in factored form set it equal to zero, solve for \(x\)

  23. anonymous
    • one year ago
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    x=-1?

  24. misty1212
    • one year ago
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    you obviously already factored the denominator as \[(x+1)(x+9)\] solve \[(x+1)(x+9)=0\] and solve for \(x\)

  25. anonymous
    • one year ago
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    -1,-9

  26. misty1212
    • one year ago
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    bingo

  27. misty1212
    • one year ago
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    that is, those are the restricted values

  28. anonymous
    • one year ago
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    ohh thank you:)

  29. anonymous
    • one year ago
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    That's all for now

  30. anonymous
    • one year ago
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    Simplify completely quantity 6 x minus 12 over 10.

  31. anonymous
    • one year ago
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    is it 3(x-5)/5

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