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anonymous

  • one year ago

If a jet is traveling 200 mi/hr due east and the side wind is 40 mi/hour south what degree and direction will the jet be traveling??

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  1. anonymous
    • one year ago
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    I think it is being moved 11.3 degrees down so 360-11 =349 degree which the direction would be south east

  2. anonymous
    • one year ago
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    |dw:1436040245429:dw|

  3. anonymous
    • one year ago
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    Not sure if this is correct because east is 0 degrees north is 90, West is 180 and south is 270. If I was going south, I would do 270 - 11 but I am going east, which is at 0 degree so does that mean I really am just going -11 degree and not 360-11 ??

  4. anonymous
    • one year ago
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    Not sure if this is correct because east is 0 degrees north is 90, West is 180 and south is 270. If I was going south, I would do 270 - 11 but I am going east, which is at 0 degree so does that mean I really am just going -11 degree and not 360-11 ??

  5. welshfella
    • one year ago
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    Note: the wind would tend to push you south

  6. nincompoop
    • one year ago
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    correct concept

  7. anonymous
    • one year ago
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    Yes, but I am going east, which is at 0 degree but east could be at 360 degree

  8. nincompoop
    • one year ago
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    then it would be southeast

  9. anonymous
    • one year ago
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    Yes I know it will be southeast but is the degree -11 or 349??

  10. nincompoop
    • one year ago
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    use the quadrant information

  11. welshfella
    • one year ago
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    the resultant direction is east:- there are 2 vectors involved here the wind direction South and the direction the plane must go in order to make the resultant due east

  12. anonymous
    • one year ago
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    Correct welshfella

  13. nincompoop
    • one year ago
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  14. anonymous
    • one year ago
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    So I go counter clockwise? so it will be 349 degrees

  15. anonymous
    • one year ago
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    |dw:1436042456997:dw|

  16. triciaal
    • one year ago
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    |dw:1436045978095:dw|

  17. triciaal
    • one year ago
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    how did you get 11?

  18. anonymous
    • one year ago
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    tan^-1 40/200 = 11 degrees on my calculator

  19. nincompoop
    • one year ago
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    there are different ways to represent directions.

  20. anonymous
    • one year ago
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    tan = opposite/adjacent which we have 200 as adjancent and 40 as opposite

  21. nincompoop
    • one year ago
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  22. nincompoop
    • one year ago
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    please read through the attachments I have provided, because whatever you're learning now will be expanded into numerous and complex ways.

  23. anonymous
    • one year ago
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    Ok, no help I will just close the question.

  24. anonymous
    • one year ago
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    I will try peeranswer

  25. nincompoop
    • one year ago
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    we are not here to provide you answers

  26. anonymous
    • one year ago
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    Thanks for trying

  27. anonymous
    • one year ago
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    Was not looking for the answer and I never do

  28. nincompoop
    • one year ago
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    triciaal spoonfed you with steps

  29. anonymous
    • one year ago
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    Tricial tan was WRONG

  30. anonymous
    • one year ago
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    How is tan^-1 40/200 = 20 she even had 5 as one of the sides

  31. triciaal
    • one year ago
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    how can tan be wrong and we have the same expression tan = (-40/200)

  32. nincompoop
    • one year ago
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    it is S not 5

  33. anonymous
    • one year ago
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    If you have as vector of 200 mph and going east with a vector coming south at 40 mph you have a tan^-1 40/200 which is 11 degrees

  34. triciaal
    • one year ago
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    I don't have 5 it is south do you see E for east?

  35. anonymous
    • one year ago
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    Your tan is wrong

  36. nincompoop
    • one year ago
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    stop helping the troll thrive @triciaal leave him be

  37. anonymous
    • one year ago
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    Well this troll will not spend another dame dime on openstudy.

  38. anonymous
    • one year ago
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    And I am reporting you

  39. anonymous
    • one year ago
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    For not being more professional like you should be

  40. nincompoop
    • one year ago
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    like I said there are different ways to represent directions you can have a clockwise rotation and there's a counter-clockwise rotation from a reference.

  41. nincompoop
    • one year ago
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    I even provided you with book references for you to read.

  42. anonymous
    • one year ago
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    Yes I know there are different ways and that is what I was asking about but I was refering to vector and and how they use the rotation. It seems they use counter clockwise from this http://www.physicsclassroom.com/Class/vectors/u3l1a.cfm, which at 11 degree gives us 349, which I put up.

  43. nincompoop
    • one year ago
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    yes, the very attachments I provided are all about vectors

  44. anonymous
    • one year ago
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    If a vector is going 200 east and then 40 south we have a tan of 40/200 which = 11 degrees or we could say -11

  45. anonymous
    • one year ago
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    But since vectors move clockwise it is 360-11

  46. nincompoop
    • one year ago
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    like i said from the beginning that if you followed the quadrant information for the components, then you wouldn't have to be bogged down with negative or positive in the end, because you already considered them from the beginning.

  47. anonymous
    • one year ago
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    Which I posted but you just posted a link and call it helping. Anyways I am finished.

  48. anonymous
    • one year ago
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    I have reported how unprofessional you are too

  49. nincompoop
    • one year ago
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    if you're facing east and moved south-east in a clockwise manner, then you're rotating negatively, then the other way is opposite you cannot scare me with report threats

  50. anonymous
    • one year ago
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    Leave I do not need your help

  51. triciaal
    • one year ago
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    OK you need both velocity and direction we agree the tan = -40/200 I might not have all the answers very quickly I am not perfect If I have a post with questions please ask for clarification I am professional sorry if I could not help more I am a qualified helper so you can give a rating at the top I will not get paid anyway since I did not give the final answer I am always happy to help

  52. nincompoop
    • one year ago
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    he didn't use -40 for his y component

  53. anonymous
    • one year ago
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    Yeah , another mistake

  54. nincompoop
    • one year ago
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    http://www.wolframalpha.com/input/?i=arctan%3D+-40%2F200 http://www.wolframalpha.com/input/?i=arctan%3D+40%2F200 look at the difference

  55. nincompoop
    • one year ago
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    if you allowed proper signs in your components, you will not have to worry whether positive or negative in the end. if you neglected it, then you will have to think about whether you want to apply a negative or positive in the end. you probably didn't set your calculator properly too

  56. anonymous
    • one year ago
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    @nincompoop @dan815 says I am correct.

  57. anonymous
    • one year ago
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    this is why I laugh at people that pay to get help on this site

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