anonymous
  • anonymous
If a jet is traveling 200 mi/hr due east and the side wind is 40 mi/hour south what degree and direction will the jet be traveling??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I think it is being moved 11.3 degrees down so 360-11 =349 degree which the direction would be south east
anonymous
  • anonymous
|dw:1436040245429:dw|
anonymous
  • anonymous
Not sure if this is correct because east is 0 degrees north is 90, West is 180 and south is 270. If I was going south, I would do 270 - 11 but I am going east, which is at 0 degree so does that mean I really am just going -11 degree and not 360-11 ??

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anonymous
  • anonymous
Not sure if this is correct because east is 0 degrees north is 90, West is 180 and south is 270. If I was going south, I would do 270 - 11 but I am going east, which is at 0 degree so does that mean I really am just going -11 degree and not 360-11 ??
welshfella
  • welshfella
Note: the wind would tend to push you south
nincompoop
  • nincompoop
correct concept
anonymous
  • anonymous
Yes, but I am going east, which is at 0 degree but east could be at 360 degree
nincompoop
  • nincompoop
then it would be southeast
anonymous
  • anonymous
Yes I know it will be southeast but is the degree -11 or 349??
nincompoop
  • nincompoop
use the quadrant information
welshfella
  • welshfella
the resultant direction is east:- there are 2 vectors involved here the wind direction South and the direction the plane must go in order to make the resultant due east
anonymous
  • anonymous
Correct welshfella
nincompoop
  • nincompoop
anonymous
  • anonymous
So I go counter clockwise? so it will be 349 degrees
anonymous
  • anonymous
|dw:1436042456997:dw|
triciaal
  • triciaal
|dw:1436045978095:dw|
triciaal
  • triciaal
how did you get 11?
anonymous
  • anonymous
tan^-1 40/200 = 11 degrees on my calculator
nincompoop
  • nincompoop
there are different ways to represent directions.
anonymous
  • anonymous
tan = opposite/adjacent which we have 200 as adjancent and 40 as opposite
nincompoop
  • nincompoop
please read through the attachments I have provided, because whatever you're learning now will be expanded into numerous and complex ways.
anonymous
  • anonymous
Ok, no help I will just close the question.
anonymous
  • anonymous
I will try peeranswer
nincompoop
  • nincompoop
we are not here to provide you answers
anonymous
  • anonymous
Thanks for trying
anonymous
  • anonymous
Was not looking for the answer and I never do
nincompoop
  • nincompoop
triciaal spoonfed you with steps
anonymous
  • anonymous
Tricial tan was WRONG
anonymous
  • anonymous
How is tan^-1 40/200 = 20 she even had 5 as one of the sides
triciaal
  • triciaal
how can tan be wrong and we have the same expression tan = (-40/200)
nincompoop
  • nincompoop
it is S not 5
anonymous
  • anonymous
If you have as vector of 200 mph and going east with a vector coming south at 40 mph you have a tan^-1 40/200 which is 11 degrees
triciaal
  • triciaal
I don't have 5 it is south do you see E for east?
anonymous
  • anonymous
Your tan is wrong
nincompoop
  • nincompoop
stop helping the troll thrive @triciaal leave him be
anonymous
  • anonymous
Well this troll will not spend another dame dime on openstudy.
anonymous
  • anonymous
And I am reporting you
anonymous
  • anonymous
For not being more professional like you should be
nincompoop
  • nincompoop
like I said there are different ways to represent directions you can have a clockwise rotation and there's a counter-clockwise rotation from a reference.
nincompoop
  • nincompoop
I even provided you with book references for you to read.
anonymous
  • anonymous
Yes I know there are different ways and that is what I was asking about but I was refering to vector and and how they use the rotation. It seems they use counter clockwise from this http://www.physicsclassroom.com/Class/vectors/u3l1a.cfm, which at 11 degree gives us 349, which I put up.
nincompoop
  • nincompoop
yes, the very attachments I provided are all about vectors
anonymous
  • anonymous
If a vector is going 200 east and then 40 south we have a tan of 40/200 which = 11 degrees or we could say -11
anonymous
  • anonymous
But since vectors move clockwise it is 360-11
nincompoop
  • nincompoop
like i said from the beginning that if you followed the quadrant information for the components, then you wouldn't have to be bogged down with negative or positive in the end, because you already considered them from the beginning.
anonymous
  • anonymous
Which I posted but you just posted a link and call it helping. Anyways I am finished.
anonymous
  • anonymous
I have reported how unprofessional you are too
nincompoop
  • nincompoop
if you're facing east and moved south-east in a clockwise manner, then you're rotating negatively, then the other way is opposite you cannot scare me with report threats
anonymous
  • anonymous
Leave I do not need your help
triciaal
  • triciaal
OK you need both velocity and direction we agree the tan = -40/200 I might not have all the answers very quickly I am not perfect If I have a post with questions please ask for clarification I am professional sorry if I could not help more I am a qualified helper so you can give a rating at the top I will not get paid anyway since I did not give the final answer I am always happy to help
nincompoop
  • nincompoop
he didn't use -40 for his y component
anonymous
  • anonymous
Yeah , another mistake
nincompoop
  • nincompoop
http://www.wolframalpha.com/input/?i=arctan%3D+-40%2F200 http://www.wolframalpha.com/input/?i=arctan%3D+40%2F200 look at the difference
nincompoop
  • nincompoop
if you allowed proper signs in your components, you will not have to worry whether positive or negative in the end. if you neglected it, then you will have to think about whether you want to apply a negative or positive in the end. you probably didn't set your calculator properly too
anonymous
  • anonymous
@nincompoop @dan815 says I am correct.
anonymous
  • anonymous
this is why I laugh at people that pay to get help on this site

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