If a jet is traveling 200 mi/hr due east and the side wind is 40 mi/hour south what degree and direction will the jet be traveling??

- anonymous

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- anonymous

I think it is being moved 11.3 degrees down so 360-11 =349 degree which the direction would be south east

- anonymous

|dw:1436040245429:dw|

- anonymous

Not sure if this is correct because east is 0 degrees north is 90, West is 180 and south is 270. If I was going south, I would do 270 - 11 but I am going east, which is at 0 degree so does that mean I really am just going -11 degree and not 360-11 ??

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## More answers

- anonymous

- welshfella

Note: the wind would tend to push you south

- nincompoop

correct concept

- anonymous

Yes, but I am going east, which is at 0 degree but east could be at 360 degree

- nincompoop

then it would be southeast

- anonymous

Yes I know it will be southeast but is the degree -11 or 349??

- nincompoop

use the quadrant information

- welshfella

the resultant direction is east:- there are 2 vectors involved here the wind direction South and the direction the plane must go in order to make the resultant due east

- anonymous

Correct welshfella

- nincompoop

##### 1 Attachment

- anonymous

So I go counter clockwise? so it will be 349 degrees

- anonymous

|dw:1436042456997:dw|

- triciaal

|dw:1436045978095:dw|

- triciaal

how did you get 11?

- anonymous

tan^-1 40/200 = 11 degrees on my calculator

- nincompoop

there are different ways to represent directions.

- anonymous

tan = opposite/adjacent which we have 200 as adjancent and 40 as opposite

- nincompoop

- nincompoop

please read through the attachments I have provided, because whatever you're learning now will be expanded into numerous and complex ways.

- anonymous

Ok, no help I will just close the question.

- anonymous

I will try peeranswer

- nincompoop

we are not here to provide you answers

- anonymous

Thanks for trying

- anonymous

Was not looking for the answer and I never do

- nincompoop

triciaal spoonfed you with steps

- anonymous

Tricial tan was WRONG

- anonymous

How is tan^-1 40/200 = 20 she even had 5 as one of the sides

- triciaal

how can tan be wrong and we have the same expression
tan = (-40/200)

- nincompoop

it is S not 5

- anonymous

If you have as vector of 200 mph and going east with a vector coming south at 40 mph you have a tan^-1 40/200 which is 11 degrees

- triciaal

I don't have 5 it is south do you see E for east?

- anonymous

Your tan is wrong

- nincompoop

stop helping the troll thrive @triciaal leave him be

- anonymous

Well this troll will not spend another dame dime on openstudy.

- anonymous

And I am reporting you

- anonymous

For not being more professional like you should be

- nincompoop

like I said there are different ways to represent directions
you can have a clockwise rotation and there's a counter-clockwise rotation from a reference.

- nincompoop

I even provided you with book references for you to read.

- anonymous

Yes I know there are different ways and that is what I was asking about but I was refering to vector and and how they use the rotation. It seems they use counter clockwise from this http://www.physicsclassroom.com/Class/vectors/u3l1a.cfm, which at 11 degree gives us 349, which I put up.

- nincompoop

yes, the very attachments I provided are all about vectors

- anonymous

If a vector is going 200 east and then 40 south we have a tan of 40/200 which = 11 degrees or we could say -11

- anonymous

But since vectors move clockwise it is 360-11

- nincompoop

like i said from the beginning that if you followed the quadrant information for the components, then you wouldn't have to be bogged down with negative or positive in the end, because you already considered them from the beginning.

- anonymous

Which I posted but you just posted a link and call it helping. Anyways I am finished.

- anonymous

I have reported how unprofessional you are too

- nincompoop

if you're facing east and moved south-east in a clockwise manner, then you're rotating negatively, then the other way is opposite
you cannot scare me with report threats

- anonymous

Leave I do not need your help

- triciaal

OK
you need both velocity and direction
we agree the tan = -40/200
I might not have all the answers very quickly I am not perfect
If I have a post with questions please ask for clarification
I am professional sorry if I could not help more
I am a qualified helper so you can give a rating at the top
I will not get paid anyway since I did not give the final answer
I am always happy to help

- nincompoop

he didn't use -40 for his y component

- anonymous

Yeah , another mistake

- nincompoop

http://www.wolframalpha.com/input/?i=arctan%3D+-40%2F200
http://www.wolframalpha.com/input/?i=arctan%3D+40%2F200
look at the difference

- nincompoop

if you allowed proper signs in your components, you will not have to worry whether positive or negative in the end. if you neglected it, then you will have to think about whether you want to apply a negative or positive in the end. you probably didn't set your calculator properly too

- anonymous

@nincompoop @dan815 says I am correct.

- anonymous

this is why I laugh at people that pay to get help on this site

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