Find the equation, in standard form, of the line passing through the points (3,-4) and (5,1).

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Find the equation, in standard form, of the line passing through the points (3,-4) and (5,1).

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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First find the slope using equation %28y2+-+y1%29%2F%28x2+-+x1%29 Make (5,1) = (x1,y1) (-2,3) = (x2,y2) Substituting %28y2+-+y1%29%2F%28x2+-+x1%29 = %283+-+1%29%2F%28-2+-+5%29=%282%29%2F%28-7%29 Now use y = mx + b as a template. m = %282%29%2F%28-7%29 as just determined. for y and x, use the point (5,1). x=5 and y =1. Substitute these values in y = mx + b y = mx + b ; 1 = (-2/7)5 + b 1 = -10/7 + b add 10/7 to each side 1 + 10/7 = b 17/7 = b So our equation is y = (-2/7)x + 17/7
you can do it the same way but with your problem
\[5 x-2 y=23 \]"Find the equation, in standard form . . ."

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