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anonymous

  • one year ago

Find the point on the terminal side of θ =-3 pi/4 that has an x coordinate of -1.

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  1. Kash_TheSmartGuy
    • one year ago
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    http://www.algebra.com/algebra/homework/Coordinate-system/Coordinate-system.faq.question.375721.html - the same questions answer and tutorial! @mathway

  2. Kash_TheSmartGuy
    • one year ago
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    no, but it's a tutorial. Plus, I was suspended for giving the answer to the question. So, this is just an example to a similar question.

  3. anonymous
    • one year ago
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    I don't want you to give me the answer. @Kash_TheSmartGuy I just want to know the steps. :)

  4. anonymous
    • one year ago
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    |dw:1436055318688:dw|

  5. anonymous
    • one year ago
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    the reference angle for -3pi/4 is pi/4. pi/4 has the same sine and cosine. angles for which pi/4 is the reference angle will then have sines and cosines that are either equal or opposites depending on the quadrant. make sense so far?

  6. ybarrap
    • one year ago
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    |dw:1436055520735:dw|

  7. anonymous
    • one year ago
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    yes.

  8. anonymous
    • one year ago
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    Does that mean that the x and y coordinates are equal?

  9. anonymous
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    So y will -1 as well since it is in quadrant 3, (-x,-y).

  11. anonymous
    • one year ago
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    that's right

  12. anonymous
    • one year ago
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    That's it? :)

  13. anonymous
    • one year ago
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    yep

  14. anonymous
    • one year ago
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    Oh and it's actually a 45-45-90 reference angle, correct?

  15. anonymous
    • one year ago
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    yes it is

  16. anonymous
    • one year ago
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    And that explains why x and y are the same. :)

  17. anonymous
    • one year ago
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    Thank you @peachpi !

  18. anonymous
    • one year ago
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    you're welcome

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