help me please?!?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

help me please?!?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
-_- we are on the same stupid site
here.. try this site it helps alot https://mathway.com/

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

let me kno if you get the answer
well first what do you get when you multiply the radicals?
8
how about the x's?
x^2?
when you have the same base you add the exponents.. so x^2(x) x^(2+1) what do you get?
x^3
great put it all together and we know it's \[\sqrt{8x ^{3}}\] right?
yes.
okay, now from here. how do we simplify radicals?
c?
uhmnot quite
okay..no. /.\
we take everything in pairs of 2 out. So let's expand this variable. \[\sqrt{2\times2\times2\times x \times x \times x}\] so what pairs can we take out?
a pair of 2's and a pair or x's.
so 2x sqrt 2x
yes!

Not the answer you are looking for?

Search for more explanations.

Ask your own question