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anonymous

  • one year ago

Write the equation of a parabola with a vertex at (10, 0) and a directrix x = 8.

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  1. anonymous
    • one year ago
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    x+10= 1/8^x2 y-10= 1/8^x2 y+10= 1/8^x2 x-10= 1/8^x2 are my choices

  2. anonymous
    • one year ago
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    @rishavraj

  3. anonymous
    • one year ago
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    anything? @baad1994

  4. anonymous
    • one year ago
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    |dw:1436071690960:dw| The distance from V to the directrix is the same from V to F So you have this: P=-2 (Negative because the parabola is open to the left) and V(8,0) The form of your equation is \[(y-k)^{2}=4p(x-h)\] where (h,k) is your V and p is the distance from V to F \[(y-0)^{2}=-4*2(x-8)\] \[(y-0)^{2}=-8(x-8)\] \[y^{2}=-8x+64\]

  5. anonymous
    • one year ago
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    the image is wrong .. is this image

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