(3+√2ˏ6+√2 ) (3−√2ˏ6−√2 ) = Find the distance between two points ? :)

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(3+√2ˏ6+√2 ) (3−√2ˏ6−√2 ) = Find the distance between two points ? :)

Mathematics
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You can use the distance formula \[\huge d = \sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}\] where your coordinates represent \[(x_1, y_1) ~~~\text{and}~~~(x_2,y_2)\] respectively.
@Loonie here is your answer
thanks :)

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Best of Luck
OpenStudy values the Learning process - not the ‘Give you an answer’ process Don’t post only answers - guide the asker to a solution. Have homework problems? We can help you - as long as you are looking to learn how to get your solution (and not just the answer). Please do not copy and paste your problems. If people are going to spend time to help you, you should at least spend the time to ask your question as clearly as possible.
why ? this is the answer ? d = √(8+8) = √16 = 4 ?
@Loonie this isn't aimed at you.... It's aimed at @geniushr What @peachpi wrote... That is from the Openstudy Code of Conduct which was obviously broken thanks to the direct answer post. This website is solely used to guide users through the process of learning the material.
Stop giving direct answers! I bet you're trying to reach 80 SS fast because of what I just typed in OpenStudy Feedback earlier. Isn't it?
right @peachpi ?
yes I probably should have tagged @geniushr to make that clear
d = √{[(3−√2)-(3+√2)]² + [(6−√2)-(6+√2)]²} d = √[(-2√2)²+(-2√2)²]
I know it :) Thanks @geniushr
Best of Luck dear :)
@geniushr Please note that you can not give to the asker the direct answer, since you have to respect the Code Of Conduct
@Michele_Laino Sorry I was not fimilier of it...
@geniushr ok!, please give your explanation to that question
@Michele_Laino she already gave the explanation :)
I meant, that we have to guide the asker in understanding of his/her question @Loonie
I know how to solve distance formula with square root :)
It is ok if @geniushr will follow the Code of Conduct :)
from now onwards :)
Yes dear I shall follow the code of conduct afterwards
thanks! :) @geniushr
thanks :)

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