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anonymous

  • one year ago

5x+4y=3 2x+6y=30 find the value of y in the solution

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  1. Astrophysics
    • one year ago
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    Any specific method?

  2. Astrophysics
    • one year ago
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    I usually enjoy using substitution method, so you can take one of the equations isolate x and plug it in for x in the second variable. So |dw:1436097947141:dw|

  3. Astrophysics
    • one year ago
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    Now we plug that in for x in the second equation |dw:1436098000135:dw| solve for y.

  4. UsukiDoll
    • one year ago
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    while substitution method can be used, it creates fractions and could be harder to solve for y. The elimination method can get to solving y faster we are given these equations 5x+4y=3 2x+6y=30 multiply the entire first equation by -2 and multiply the entire second equation by 5 After that.. add them together and solve for y

  5. UsukiDoll
    • one year ago
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    sorry I forgot... if we add these 2 equations together (after what I mentioned) the x variable should disappear.

  6. anonymous
    • one year ago
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    5x+4y=3 5x = 3 - 4y x = (3-4y)/5 put in 2nd eqyation: 2x+6y=30 2(3-4y)/5 +6y = 30 6-8y+30y = 150 22y = 144 y = 72/11

  7. anonymous
    • one year ago
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    OpenStudy values the Learning process - not the ‘Give you an answer’ process Don’t post only answers - guide the asker to a solution. Have homework problems? We can help you - as long as you are looking to learn how to get your solution (and not just the answer). Please do not copy and paste your problems. If people are going to spend time to help you, you should at least spend the time to ask your question as clearly as possible.

  8. anonymous
    • one year ago
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    I don't think you need my help here :)

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