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anonymous
 one year ago
5x+4y=3
2x+6y=30
find the value of y in the solution
anonymous
 one year ago
5x+4y=3 2x+6y=30 find the value of y in the solution

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Any specific method?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4I usually enjoy using substitution method, so you can take one of the equations isolate x and plug it in for x in the second variable. So dw:1436097947141:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Now we plug that in for x in the second equation dw:1436098000135:dw solve for y.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2while substitution method can be used, it creates fractions and could be harder to solve for y. The elimination method can get to solving y faster we are given these equations 5x+4y=3 2x+6y=30 multiply the entire first equation by 2 and multiply the entire second equation by 5 After that.. add them together and solve for y

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2sorry I forgot... if we add these 2 equations together (after what I mentioned) the x variable should disappear.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05x+4y=3 5x = 3  4y x = (34y)/5 put in 2nd eqyation: 2x+6y=30 2(34y)/5 +6y = 30 68y+30y = 150 22y = 144 y = 72/11

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OpenStudy values the Learning process  not the ‘Give you an answer’ process Don’t post only answers  guide the asker to a solution. Have homework problems? We can help you  as long as you are looking to learn how to get your solution (and not just the answer). Please do not copy and paste your problems. If people are going to spend time to help you, you should at least spend the time to ask your question as clearly as possible.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't think you need my help here :)
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