anonymous
  • anonymous
Write the equation of the line that passes through (–2, 6) and (2, 14) in slope-intercept form
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
First, put your points in a coordinate axis |dw:1436122718297:dw| operating a=8 b=4 the form of your equation is: \[y=mx+i\] where m:slope i:Intercept so you need the slope and the intercept you can find the slope with this expression \[m=tg \alpha=\frac{ a }{ b }=\frac{ 8 }{ 4 }=2\] this is the equation of your line \[y=2x+i\] and you have two points of this. Replace one of the points in your equation for (-2,6): x=-2 y=6 \[6=2(-2)+i\] \[10=i\] \[y=2x+10\]
anonymous
  • anonymous
y = 2x + 10 correct answer
anonymous
  • anonymous
y-6 = {(14-6)/[2-(-2)]} x {x-(-2)} y-6 = 2(x+2) y = 2x +10 <>

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