## anonymous one year ago Write the equation of the line that passes through (–2, 6) and (2, 14) in slope-intercept form

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1. anonymous

First, put your points in a coordinate axis |dw:1436122718297:dw| operating a=8 b=4 the form of your equation is: $y=mx+i$ where m:slope i:Intercept so you need the slope and the intercept you can find the slope with this expression $m=tg \alpha=\frac{ a }{ b }=\frac{ 8 }{ 4 }=2$ this is the equation of your line $y=2x+i$ and you have two points of this. Replace one of the points in your equation for (-2,6): x=-2 y=6 $6=2(-2)+i$ $10=i$ $y=2x+10$

2. anonymous

y = 2x + 10 correct answer

3. anonymous

y-6 = {(14-6)/[2-(-2)]} x {x-(-2)} y-6 = 2(x+2) y = 2x +10 <<y=mx+c form>>