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anonymous

  • one year ago

Given that S^3 on the bottom 1 (e^x)dx=(e^3)-e use the properties of integrals and this result to evaluate S^3 on the bottom 1 (5e^x − 1) dx. I got 5e^3x-5e-1 is this correct? Please help!

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  1. sparrow2
    • one year ago
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    i didn't get what bottom?

  2. anonymous
    • one year ago
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    |dw:1436131237742:dw|

  3. sparrow2
    • one year ago
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    so integral?> we need to find an integral or solve equation? or what>?

  4. anonymous
    • one year ago
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    evaluate

  5. anonymous
    • one year ago
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    |dw:1436131640196:dw|

  6. sparrow2
    • one year ago
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    oh ok

  7. sparrow2
    • one year ago
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    |dw:1436120897687:dw|

  8. anonymous
    • one year ago
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    I had 5(e^3x -1)-(1)(1)

  9. anonymous
    • one year ago
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    where did the 3 and +1 come from?

  10. sparrow2
    • one year ago
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    do you know integration?

  11. sparrow2
    • one year ago
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    when you have numbers

  12. sparrow2
    • one year ago
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    |dw:1436121144797:dw|

  13. sparrow2
    • one year ago
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    keep this in mind, newton-leibniz formula(if i remember correctly,i mean the name,formula is correct :D )

  14. anonymous
    • one year ago
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    oh okay thank you!

  15. anonymous
    • one year ago
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    i just did it again (5e^3-1)-(5e^1-1)=5e^3-1-5e+1 im still not getting the 3?

  16. anonymous
    • one year ago
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    @sparrow2

  17. sparrow2
    • one year ago
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    watch my integration

  18. sparrow2
    • one year ago
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    it is 5e^x-x not 5e^x-1 after integration

  19. sparrow2
    • one year ago
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    i need help with my english thoug :D

  20. anonymous
    • one year ago
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    oh okay got it! thanks!

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