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anonymous
 one year ago
Simplify the rational expression. State any restrictions on the variable.
anonymous
 one year ago
Simplify the rational expression. State any restrictions on the variable.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ n^410n^2+24 }{ n^49^2+18 }\]

math&ing001
 one year ago
Best ResponseYou've already chosen the best response.0First lets find the restrictions. For that we solve for n : n^4  9^2 + 18 = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Than what? @math&ing001

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Let \(n^2 = y\) then try simplifying the expression.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Please help me I know its \[\frac{ n^24 }{ n^23}\] but i dont know the other half for my answer, so it's between AC for the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(n+2)(n−2)(n2−6) (n2−3)(n2−6)

Hero
 one year ago
Best ResponseYou've already chosen the best response.1How do you know it's \(\dfrac{n^2  4}{n^2  3}\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(n+2)(n−2)(n2−6) (n2−3)(n2−6)

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Multiply it back out to see if what you get matches the original expression.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Also the original expression you posted likely has a typo in it somewhere.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino can you please help me finish my math problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just need help with the end of the problem. I think the answer is B though

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1@EllenJaz17 Please confirm that the problem is indeed: \(\Large \frac{ n^410n^2+24 }{ n^49\color{red}{n}^2+18 } \)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: we can factorize the denominator, using the same procedure for numerator, so we can write this: \[{n^4}  9{n^2} + 18 = \left( {{n^2}  6} \right)\left( {{n^2}  3} \right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(n+2)(n−2)(n2−6) (n2−3)(n2−6)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ n^24 }{ n^23 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know thats the answer to the first half but i need to find out the second half

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3the denominator is equal to zero when these two conditions hold: \[\begin{gathered} {n^2}  6 = 0 \hfill \\ \hfill \\ {n^2}  3 = 0 \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3please remember, that we can not divide by zero

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3please solve those quadratic equations for n, what do you get?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3are you sure? we have 6^2= 36, and 3^2=9

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No im not sure im just guessing

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: the solution to this equation: \[{n^2}  k = 0\] are: \[n = \sqrt k ,\quad n =  \sqrt k \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3since: \[{\left( {\sqrt k } \right)^2} = {\left( {  \sqrt k } \right)^2} = {n^2}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3being k a positive number or k=0

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3no, I don't think so, sorry!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: what are the solution of this equation: \[{n^2}  3 = 0\] ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So that only leaves A & C correct? because D isn't \[\frac{ n^24 }{ n^23 }\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3yes! and what is n=...?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[n \neq \pm \sqrt{6}\pm \sqrt{3}?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3from this equation: \[{n^2}  3 = 0\] I get \[n = \pm \sqrt 3 \] am I right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3ok! so we have to exclude those 2 values, since when: \[n = \pm \sqrt 3 \] the denominator is zero Now do the same with the equation: \[{n^2}  6 = 0\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3perfect, we have to exclude those values too, since when: \[n = \pm \sqrt 6 \] the denominator is zero. So what is the right option?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3that's right! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much for teaching me how to get to the answer!
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