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anonymous
 one year ago
Could someone please help me verify the trig. equation using identities?
1+sec^2xsin^2x=sec^2x
anonymous
 one year ago
Could someone please help me verify the trig. equation using identities? 1+sec^2xsin^2x=sec^2x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you could start by the first part of the equality \[1+\sec^{2}x*sen^{2}x\] you have to remember these identities : \[secx=1/cosx\] \[sen^{2}x+cos^{2}x=1\] replacing \[1+\frac{ 1^{2} }{\cos^{2}x }*sen^{2}x\] \[\frac{ cos^{2}x+sen^{2}x }{\cos^{2}x}\] \[\frac{ 1 }{\cos^{2}x}=sec^{2}x\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much! @baad1994 Could you help me with one more? 5tan^2x+sec^2x=1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And haha, I actually understood what steps you took. (: So thank you so much!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nice! :) , are you sure that there is a 5 before tan^2x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, sorry. I meant tan^2x not 5tan^2x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok , no problem n.n \[tg^{2}x+\sec^{2}x=1\] the same, start by the first part \[tg^{2}x+\sec^{2}x\] Remember these: 1)\[tgx=\frac{ senx }{ cosx }\] 2)\[secx=\frac{ 1 }{ cosx }\] 3)\[sen ^{2}x+\cos ^{2}x = 1 \] \[\cos ^{2}x = 1sen ^{2}x \] replacing \[\frac{ senx^{2} }{ cosx^{2} }+\frac{ 1 }{ cosx^{2} }\] \[\frac{ 1sen^{2}x }{ \cos ^{2}x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when you are going to verify trigonometric expressions you usually have to pass all to sen and cos. And remember that sen^2x+cos^2x=1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so remember the equivalences: secx=1/cosx cscx=1/senx tgx=senx/cosx ctgx=cosx/senx and operate
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