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- anonymous

I WILL FAN AND MEDAL
A random sample of 100 undergraduate students at a university found that 78 of them had used the university library’s website to find resources for a class. What is the margin of error for the true proportion of all undergraduates who had used the library’s website to find resources for a class?
0.04
0.08
0.1
0.12

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- anonymous

- schrodinger

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- moazzam07

margin of error suggests a confidence interval, but no width has been suggested

- moazzam07

if we wanted to be 99% confident that the true population proportion was within a given interval, we would use z=2.576 and use the standard error as a multiplier

- moazzam07

the standard error is just a modification of the standard deviation.
in this case: and i dont really understand why, the binomial standard deviation is sqrt(npq) with a mean of np (the mean i get)
z=x−npnpq−−−√
z=x−npnnpq√n
z=xn−pnpqn2−−−√
z=xn−ppqn−−√
zpqn−−−√=xn−p
pmidpoint±zpqn−−−√margin of error=±xnend points

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- moazzam07

sorry dont know how to insert equations

- moazzam07

my PC wont do it

- moazzam07

Hint: use the central limit theorem, and use a maximum value for the standard deviation for a bernouli random variable.

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