anonymous
  • anonymous
I WILL FAN AND MEDAL A random sample of 100 undergraduate students at a university found that 78 of them had used the university library’s website to find resources for a class. What is the margin of error for the true proportion of all undergraduates who had used the library’s website to find resources for a class? 0.04 0.08 0.1 0.12
Mathematics
schrodinger
  • schrodinger
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moazzam07
  • moazzam07
margin of error suggests a confidence interval, but no width has been suggested
moazzam07
  • moazzam07
if we wanted to be 99% confident that the true population proportion was within a given interval, we would use z=2.576 and use the standard error as a multiplier
moazzam07
  • moazzam07
the standard error is just a modification of the standard deviation. in this case: and i dont really understand why, the binomial standard deviation is sqrt(npq) with a mean of np (the mean i get) z=x−npnpq−−−√ z=x−npnnpq√n z=xn−pnpqn2−−−√ z=xn−ppqn−−√ zpqn−−−√=xn−p pmidpoint±zpqn−−−√margin of error=±xnend points

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moazzam07
  • moazzam07
sorry dont know how to insert equations
moazzam07
  • moazzam07
my PC wont do it
moazzam07
  • moazzam07
Hint: use the central limit theorem, and use a maximum value for the standard deviation for a bernouli random variable.

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