icalibear
  • icalibear
Simplify to just one term (1−5/6x)÷1x−5/6x2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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icalibear
  • icalibear
\[(1- \frac{ 5 }{ 6x })\div \frac{ 1 }{ x}-\frac{ 5 }{ 6x^2 }\]
anonymous
  • anonymous
Try a common denominator of 6x for the terms in parentheses then subtract
icalibear
  • icalibear
I think I'm supposed to flip the second one and multiply across?

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icalibear
  • icalibear
I also feel like some things would cancel?
anonymous
  • anonymous
when you divide, yes. but first you have to handle the subtraction in parentheses
icalibear
  • icalibear
Actually there are no parentheses in the question I just put them there to separate the two
icalibear
  • icalibear
ugh
anonymous
  • anonymous
or is the problem supposed to be |dw:1436129278158:dw|
icalibear
  • icalibear
right
icalibear
  • icalibear
that's the problem
anonymous
  • anonymous
that's a much easier problem :)
icalibear
  • icalibear
OK good lol
anonymous
  • anonymous
the denominators are 6x, x, and 6x², so their lcm (aka common denominator) is 6x². Multiplying the top and bottom by 6x² will cancel the fractions. |dw:1436129426746:dw|
anonymous
  • anonymous
crud wait. supposed to be 6x²
anonymous
  • anonymous
|dw:1436129523649:dw|
icalibear
  • icalibear
ok.. i did and its a little confusing
anonymous
  • anonymous
can you put up what you have so I can make sure we're on the same page?
icalibear
  • icalibear
sorry having trouble
icalibear
  • icalibear
yeah ill draw it
anonymous
  • anonymous
no problem. site's pretty glitchy sometimes
icalibear
  • icalibear
|dw:1436129702310:dw|
icalibear
  • icalibear
for the numerator?
anonymous
  • anonymous
|dw:1436129833564:dw|
anonymous
  • anonymous
so the numerator is\[6x^2-5x\]
icalibear
  • icalibear
why is it 6x^2 - 5x if the 6x^2 cancels to give -5? :s
anonymous
  • anonymous
the 6x² came from the 1. The -5x came from 5/(6x). You get both parts when you distribute
icalibear
  • icalibear
oh i see
icalibear
  • icalibear
why is it (-)
icalibear
  • icalibear
if we are multpying
anonymous
  • anonymous
b/c it was (-) originally and multiplied by a positive
icalibear
  • icalibear
okay
icalibear
  • icalibear
im gonna try the denominator..
anonymous
  • anonymous
ok
icalibear
  • icalibear
|dw:1436130516707:dw|
icalibear
  • icalibear
am i not cancelling when I need to
anonymous
  • anonymous
It looks like you multiplied both numerator and denominator by 6x². In fraction form \(6x^2=\frac{ 6x^2 }{ 1 }\). So only the numerator gets multiplied by it. |dw:1436130729399:dw|
anonymous
  • anonymous
You can cancel before you multiply or after. It doesn't matter. The result will be the same
anonymous
  • anonymous
do whatever you feel more comfortable with
icalibear
  • icalibear
oh okay so now I just have 6x^2 - 5x / 1/x - 5/6x^2?
icalibear
  • icalibear
and the 6x^2 cancels?
anonymous
  • anonymous
not quite: see below |dw:1436130975170:dw|
anonymous
  • anonymous
|dw:1436131068044:dw|
anonymous
  • anonymous
So you get 6x - 5 for the denominator.
anonymous
  • anonymous
and the whole thing is\[\frac{ 6x^2-5x }{ 6x-5 }\]
anonymous
  • anonymous
See where that all came from?
icalibear
  • icalibear
yes i see now. I thought you meant not to distrubute 6x^2 into any of the denominator
icalibear
  • icalibear
now to make it one term?
anonymous
  • anonymous
ah ok. sorry that wasn't clear. all that's left is to factor out an x on the numerator then you can cancel what's left
icalibear
  • icalibear
is it just x?
icalibear
  • icalibear
x(6x -5) / 6x - 5
anonymous
  • anonymous
yes. just x
icalibear
  • icalibear
oh okay. thanks so much i know that took me a while. XD
anonymous
  • anonymous
you're welcome

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