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anonymous

  • one year ago

Foil (ax+b)(cy+d)

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  1. anonymous
    • one year ago
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    \[acxy+adx+bcy+bd\]

  2. anonymous
    • one year ago
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    1. Prove that it is true through an algebraic proof, identifying each step 2. Demonstrate that your polynomial identity works on numerical relationships

  3. anonymous
    • one year ago
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    I don't know what to do with those 2 questions. Any ideas?

  4. anonymous
    • one year ago
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    wouldn't it be axcy+axb+bcy+bd?

  5. anonymous
    • one year ago
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    the second one is simple,just put numbers and check that the output is the same

  6. anonymous
    • one year ago
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    Can we work it out together? I'm a little slow today :)

  7. anonymous
    • one year ago
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    @Armi Okay so how would I do this?

  8. anonymous
    • one year ago
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    @Kfsv10 Please help! I will medal/fan

  9. anonymous
    • one year ago
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    @userbuggg323 use the foil method .... axcy + axd+ bcy+ bd

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spraguer (Moderator)
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