ALGEBRA 2 WILL GIVE MEDAL

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ALGEBRA 2 WILL GIVE MEDAL

Trigonometry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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What are the amplitude, period, and midline of the function? Amplitude: 4; period: 2π; midline: y = −1 Amplitude: 8; period: 2π; midline: y = 1 Amplitude: 8; period: π; midline: y = −1 Amplitude: 4; period: π; midline: y = 1
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Use graph
Amplitude is half of the distance between the highest lowest points. The top and bottom points are 3 and -5, respectively. The distance between is 8, so the amplitude is half of 8, or 4.

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Other answers:

so b?
First, we have to determine what the other 2 are. And second, B says that the amplitude is 8, so it can't be B.
Oh ok so
It will be A or D
D
Let's figure out what the period is. The period is the distance between the point on any wave and the same point on another wave. Kinda complicated way to say it, so a simpler way is just the distance between the tops of the waves. What is the horizontal difference between the top of two of the waves?
4
The distance of the red line in http://prntscr.com/7p9t23
3
Are you sure? Look at the number on the line.
Its 4
The amplitude is 4, but we're talking about the period here
Thats 3???
OH
Remember, it's horizontal distance, not vertical
2!
2 what? There's something after the 2.
Pi
Yeah, it's \(2\pi\) So it has amplitude of 4 and period of \(2\pi\). Which choice is that?
A
can u help me w a few more
Correct :)
Sure, I can help with a few more, just tag me in a separate question. :)

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