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anonymous
 one year ago
The diagram shows the aerial view of a park. What is the length of the park's boundary to the nearest yard? Use the value π = 3.14.
215 yards
266 yards
285 yards
309 yards
http://cdn.ple.platoweb.com/PCAPASSETSPROD/6ba968e838ff470d8f9f18b417492d85
anonymous
 one year ago
The diagram shows the aerial view of a park. What is the length of the park's boundary to the nearest yard? Use the value π = 3.14. 215 yards 266 yards 285 yards 309 yards http://cdn.ple.platoweb.com/PCAPASSETSPROD/6ba968e838ff470d8f9f18b417492d85

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0assuming that the limits are the perimeter of this park: dw:1436148213050:dw and for the left and right \[L=\theta*R\] theta is in rad \[\frac{ 120 \pi }{ 180 } = \frac{ 2 \pi }{ 3 }\] \[L= \frac{ 2 \pi }{ 3 }*50=104.7\] calculating the perimeter: \[2*50+2*104.7=309.4\] I think that the answer is 309

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0@baad1994 You are correct. You can also use the formula \(s = \dfrac{x}{360^o} \times 2 \pi r\) for the length of an arc and avoid having to convert to radians. \(P = 2 \times \left( \dfrac{120}{360}\times 2 \pi \times 50 ~yd \right) + 2 \times 50~yd = 309 ~yd\)
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