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anonymous

  • one year ago

Which of the following would best represent a cosine function with an amplitude of 3, a period of pi over 2, and a midline at y = −4? f(x) = −4 cos 4x + 3 f(x) = 3 cos(x − pi over 2) − 4 f(x) = 4 cos(x − pi over 2) + 3 f(x) = 3 cos 4x − 4

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  1. anonymous
    • one year ago
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    @LegendarySadist

  2. anonymous
    • one year ago
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    The amplitude is the number before the trig function (sine, cosine, etc.). So we want a 3 before the cos in this case.

  3. anonymous
    • one year ago
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    ok

  4. anonymous
    • one year ago
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    can u help

  5. anonymous
    • one year ago
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    It will usually be written out like this \[\large acos(bx-c)+d\\\large amplitude~=~a\\\\\large period~=~\frac{2pi}{b}\]

  6. anonymous
    • one year ago
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    The midline is the point halfway between the top and bottom of the wave. The midline of a cos function is usually 0. So to change it to 4 smaller, we have to make the vertical change (the d in my example) equal -4. So set d=-4

  7. anonymous
    • one year ago
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    A

  8. anonymous
    • one year ago
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    Wrong. Did you just guess?

  9. anonymous
    • one year ago
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    No

  10. anonymous
    • one year ago
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    Nevermind i figured it out thanks anyways

  11. anonymous
    • one year ago
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    \[\large amplitude=a\\\large amplitude=3\\\large a=3\] So in \(\large acos(bx)+d\), \(\large a=3\)

  12. anonymous
    • one year ago
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    So did you get the answer then?

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