Which of the following would best represent a cosine function with an amplitude of 3, a period of pi over 2, and a midline at y = −4? f(x) = −4 cos 4x + 3 f(x) = 3 cos(x − pi over 2) − 4 f(x) = 4 cos(x − pi over 2) + 3 f(x) = 3 cos 4x − 4

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Which of the following would best represent a cosine function with an amplitude of 3, a period of pi over 2, and a midline at y = −4? f(x) = −4 cos 4x + 3 f(x) = 3 cos(x − pi over 2) − 4 f(x) = 4 cos(x − pi over 2) + 3 f(x) = 3 cos 4x − 4

Trigonometry
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The amplitude is the number before the trig function (sine, cosine, etc.). So we want a 3 before the cos in this case.
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can u help
It will usually be written out like this \[\large acos(bx-c)+d\\\large amplitude~=~a\\\\\large period~=~\frac{2pi}{b}\]
The midline is the point halfway between the top and bottom of the wave. The midline of a cos function is usually 0. So to change it to 4 smaller, we have to make the vertical change (the d in my example) equal -4. So set d=-4
A
Wrong. Did you just guess?
No
Nevermind i figured it out thanks anyways
\[\large amplitude=a\\\large amplitude=3\\\large a=3\] So in \(\large acos(bx)+d\), \(\large a=3\)
So did you get the answer then?

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