How many molecules (not moles) of NH3 are produced from 5.01×10−4 g of H2?

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How many molecules (not moles) of NH3 are produced from 5.01×10−4 g of H2?

Chemistry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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1. Set up your balanced equation. 3H2 + N2 ---> 2NH3
If you look at what I wrote, here's how you can set this up. 1. You must first find the balanced chemical reaction. 2. You must convert grams of your substance in this case hydrogen gas into moles. 3. You must multiply the molar ratio in this case NH3/H2 which is 2/3 ensuring that the compound you want NH3 is in the numerator, and while the compound you don't want, H2 is in the denominator. 4. You get the number of moles of NH3. 5. You know that 1 mole has 6.02x10^23 particles. 6. Set up a ratio cross multiply and you get the number of particles.
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