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anonymous
 one year ago
plz help fan medal and testimonial
which of the following are continuus for all real values of x?
I. f(x)= x^2+5/x^21
ii. g(X)= 3/x^2+1
iii. h(X)={x1}
choices
ii and iii only
I and ii only
I only
ii only
anonymous
 one year ago
plz help fan medal and testimonial which of the following are continuus for all real values of x? I. f(x)= x^2+5/x^21 ii. g(X)= 3/x^2+1 iii. h(X)={x1} choices ii and iii only I and ii only I only ii only

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know for a fact that choice b is wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 @Math2400 @Camila1315 @notyourdroid

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3for the two fractions you can find where they are not continuous by finding when the denominator is zero

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3h(x)=x1 is just a line then

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3do you have any questions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so my suspicion was right lol h(X)=x1 is my answer? lol

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3did you find when the bottoms were zero (if any values) for the first two?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there continuous but I put I and ii as my answer before and I was told it was wrong.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3I assume the first fraction is: \[f(x)=\frac{x^2+5}{x^21} \\ \text{ can you solve } x^21=0 \\ \text{ the second fraction is } g(x)=\frac{3}{x^2+1} \\ \text{ can you solve } x^2+1=0\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3x^21=0 x^2=1 x=1 or x=1 right? but how is 1^2+1 zero?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3so f is discontinuous at x=1 and also x=1 but what do you notice about x^2+1=0?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3no (1)^2+1 is not zero (1)^2+1 is not zero

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3both (1)^2+1 and (1)^2+1 is 1+1 which is 2

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3if I write x^2+1=0 as x^2=1 If i try to think of a positive number to plug in...I'm gonna have to square it but you know a positive times a positive =? or if i try to think of a negative number to plug in...I'm gonna have to square it but you know a negative times a negative=? or if I plug in 0 which still isn't gonna work because 0^2 is not 1

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3I'm asking you to tell me what a positive times a positive will give and what a negative times a negative will give

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1{x} usually refers to the fractional part of x

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3right x^2 is always positive or 0 1 is negative there is no way x^2 can even be 1 over the real numbers

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3there is no real solution to x^2+1=0

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3therefore g=3/(x^2+1) has no discontinuities ok so h(x)=x1 or h(x)={x1} @magy33 ?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3I'm asking since @ganeshie8 pointed out { } means fractional part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0h(x)= x1 but does the {} really have anything to do with the equation itself? I askto be sure for next time :)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3If it is there, it does

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. I think then that from my understanding the answer is ii and iii

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1I'm inclining toward ii only

myininaya
 one year ago
Best ResponseYou've already chosen the best response.3me to if h={x1} and not x1

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1the fractional function `h(x) = {x1}` is discontinuous at every integer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol I was half right. thnks for the help guys. lol I still have more questions to go before im done lol I see if I can answer if not ill post lol
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