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I know for a fact that choice b is wrong.

what does { } mean?

parenthesis

so h(x)=x-1?

yes

h(x)=x-1 is just a line then

do you have any questions?

so my suspicion was right lol h(X)=x-1 is my answer? lol

I didn't say that

did you find when the bottoms were zero (if any values) for the first two?

there continuous but I put I and ii as my answer before and I was told it was wrong.

x=1 for both

x^2-1=0
x^2=1
x=1 or x=-1
right?
but how is 1^2+1 zero?

so f is discontinuous at x=1 and also x=-1
but what do you notice about x^2+1=0?

same as the first.

no
(1)^2+1 is not zero
(-1)^2+1 is not zero

both (1)^2+1 and (-1)^2+1 is 1+1 which is 2

okay...

{x} usually refers to the fractional part of x

+ x + = +
- x - = +

there is no real solution to x^2+1=0

I'm asking since @ganeshie8 pointed out { } means fractional part

If it is there, it does

http://mathworld.wolfram.com/FractionalPart.html

ok. I think then that from my understanding the answer is ii and iii

I'm inclining toward ii only

me to if h={x-1} and not x-1

the fractional function `h(x) = {x-1}` is discontinuous at every integer