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anonymous
 one year ago
If a meterstick moves to your right at a constant velocity of 0.8c, what would you measure its length to be?
anonymous
 one year ago
If a meterstick moves to your right at a constant velocity of 0.8c, what would you measure its length to be?

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Length contraction

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge L = \frac{ L_0 }{ \gamma } = L_0 \sqrt{1\frac{ v^2 }{ c^2 }}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[L_0\] is your proper length, L is the length observed by an observer in relative motion (respect to the object), v is your relative velocity, and finally c is the speed of light

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think the answers 0.6m, what do you think?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[L_0 = 1m\] \[v = 0.8c\] \[L = 1m \times \sqrt{1\frac{ (0.8c)^2 }{ c^2 }} = \sqrt{1\frac{ 0.64c^2 }{ c^2 }}m = 0.6m ~~ \checkmark\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0xD Thanks for le confirmation fwendo :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but just to be sure, do you cancel out the c^2 or smt?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, it gets cancelled out

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436160757936:dw
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