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Epicteatime

  • one year ago

If a meterstick moves to your right at a constant velocity of 0.8c, what would you measure its length to be?

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  1. epicteatime
    • one year ago
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    @nincompoop

  2. epicteatime
    • one year ago
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    anyoneee

  3. epicteatime
    • one year ago
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    @aaronq

  4. Astrophysics
    • one year ago
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    Length contraction

  5. Astrophysics
    • one year ago
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    \[\huge L = \frac{ L_0 }{ \gamma } = L_0 \sqrt{1-\frac{ v^2 }{ c^2 }}\]

  6. Astrophysics
    • one year ago
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    \[L_0\] is your proper length, L is the length observed by an observer in relative motion (respect to the object), v is your relative velocity, and finally c is the speed of light

  7. epicteatime
    • one year ago
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    yep that xD

  8. epicteatime
    • one year ago
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    I think the answers 0.6m, what do you think?

  9. Astrophysics
    • one year ago
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    \[L_0 = 1m\] \[v = 0.8c\] \[L = 1m \times \sqrt{1-\frac{ (0.8c)^2 }{ c^2 }} = \sqrt{1-\frac{ 0.64c^2 }{ c^2 }}m = 0.6m ~~ \checkmark\]

  10. epicteatime
    • one year ago
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    HUDDAH!

  11. epicteatime
    • one year ago
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    xD Thanks for le confirmation fwendo :D

  12. Astrophysics
    • one year ago
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    Np :)

  13. epicteatime
    • one year ago
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    but just to be sure, do you cancel out the c^2 or smt?

  14. Astrophysics
    • one year ago
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    Yes, it gets cancelled out

  15. epicteatime
    • one year ago
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    ah, thanks xD

  16. Astrophysics
    • one year ago
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    |dw:1436160757936:dw|

  17. epicteatime
    • one year ago
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    :D

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