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anonymous

  • one year ago

help please

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    thank you so much

  3. anonymous
    • one year ago
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  4. anonymous
    • one year ago
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    i really need to finish my online class for the summer by 2morrow and i only have 17 questions left

  5. UnkleRhaukus
    • one year ago
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    for the first one, the sector is half a circle

  6. UnkleRhaukus
    • one year ago
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    do you remember the area of a circle?

  7. UnkleRhaukus
    • one year ago
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    @senpai_yerm

  8. anonymous
    • one year ago
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    oh srry no

  9. UnkleRhaukus
    • one year ago
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    The area of a full circle, (or radius \(r\) and diameter \(d\)) is \[A_\text{circle}=\pi r^2 = \pi\left(\frac d2\right)^2 \]

  10. UnkleRhaukus
    • one year ago
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    Our sector is not a full circle (360°), but only 180° \[A_\text{sector}=\frac{180°}{360°}A_\text{circle }\\ \qquad=\frac12A_\text{circle}\\ \qquad=\tfrac12\pi r^2\\ \qquad=\tfrac12\pi\left(\frac d2\right)^2 \]

  11. anonymous
    • one year ago
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    what do u think inkyvoyd

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