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anonymous

  • one year ago

fan medal and testimonial what is the average rate of change of y with respect to x over the interval { 1,5} for the function y=4x+2? choices: 8 1/4( wrong) 2 4

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  1. Haseeb96
    • one year ago
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    differentiate both sides of this function with respect to x |dw:1436163187408:dw|

  2. Haseeb96
    • one year ago
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    now dy/dx is showing speed

  3. anonymous
    • one year ago
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    oh that makes more sense I see what id id wrong lol

  4. Haseeb96
    • one year ago
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    in order to find average rate of change during the interval { 1,5} we use this formula

  5. Haseeb96
    • one year ago
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    |dw:1436163315029:dw|

  6. anonymous
    • one year ago
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    can you help me with two more uestions I have tried answering them and keep getting them wrong.

  7. Haseeb96
    • one year ago
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    okay tag me there

  8. Haseeb96
    • one year ago
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    if you like my explanation click at best response

  9. anonymous
    • one year ago
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    the height ,s , of a ball thrown straight down with initial speed 64ft/ sec froma cliff 80 ft. high is s(t)=-16t^2-64t+80, where t is the time elapsed that the ball is in the air. what is the instantaneous velocity of the ball when it hits the ground? 256 -96 0 112

  10. anonymous
    • one year ago
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    evaluate lim x->2 f(x) for f(x)= |dw:1436163800477:dw|

  11. myininaya
    • one year ago
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    average rate of change of y respect to x over the interval [1,5] is \[\frac{f(5)-f(1)}{5-1} \text{ where} f(x)=4x+2\] or since f(x)=4x+2 is just a line you could use the slope of this line to determine the average rate of change over any given interval

  12. myininaya
    • one year ago
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    to find velocity just differentiate the position function

  13. myininaya
    • one year ago
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    but you will have to find when s=0 first

  14. myininaya
    • one year ago
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    since it wants to know the velocity when it hits the ground (means height is 0 there so that is why we set s=0)

  15. myininaya
    • one year ago
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    for the last one you will need to consider the left and right limits

  16. Haseeb96
    • one year ago
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    |dw:1436164260135:dw|

  17. anonymous
    • one year ago
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    what bout 2 and 3?

  18. myininaya
    • one year ago
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    well have you solved s=0 yet?

  19. myininaya
    • one year ago
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    and then differentiated s to find v

  20. anonymous
    • one year ago
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    I got 80

  21. myininaya
    • one year ago
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    how did you 80 from solving the equation s=0

  22. myininaya
    • one year ago
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    \[-16t^2-64t+80=0 \\ \text{ you could divide both sides by -16 } \\ t^2+4t+5=0\] can you see if you can solve that?

  23. myininaya
    • one year ago
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    now this will tell us the value t such that s=0

  24. myininaya
    • one year ago
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    s=0 means the height=0 we want to find t such that when this happens so we can find the velocity when the ball hits the ground

  25. anonymous
    • one year ago
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    oh ok

  26. myininaya
    • one year ago
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    oops t^2+4t-5=0

  27. Haseeb96
    • one year ago
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    is it -196 ?>

  28. myininaya
    • one year ago
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    have you solved for t yet?

  29. anonymous
    • one year ago
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    not one of my choices for number 2

  30. myininaya
    • one year ago
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    I don't know if you still need help or not...

  31. anonymous
    • one year ago
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    I don't have an answer for number 2 or 3 lol I have tried everythig

  32. myininaya
    • one year ago
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    have you actually tried solving the equation I have asked you to yet/

  33. myininaya
    • one year ago
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    and then differentiating the position function to find the velocity function and then entering the number you found from solving s=0 into velocity function to find the velocity when the ball hits the ground

  34. anonymous
    • one year ago
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    yes and I am getting big numbers im terrible at it. this is hwat I got- -96 is that right?

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