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|dw:1436166754136:dw|

What do you need help solving

find cosx

Do you know the relationship between cosx and sinx?

no

|dw:1436174086784:dw|

cosx = (root8)/3

|dw:1436167048145:dw|

x=2?

|dw:1436174284089:dw|

when i say,

|dw:1436167321407:dw|

what does this mean?

sin x =1/3
Find cos x

the question is that.

i don't get what it's asking me??

\[cosx = 2\sqrt{2}/3\]

DOES X MEAN INVERSE?

Huh? No they put x there to represent it's an unkown, and that's what you're solving for

|dw:1436167875535:dw| x is the adjacent side that will help you find cosx

ohh it shows me the answer is |dw:1436167868096:dw|

Well, lets see if its right

So yes, it simplifies to \[\frac{ 2\sqrt{2} }{ 3 }\]

Something not make sense there?

wait i'm trying to understand.

No worries, take your time

Yeah, the pythagorean identity in terms of trig functions is written: \[
\sin^2x+\cos^2x =1
\]

omg so many people viewing my question.

Haha, don't get overwhelmed @Mindblast3r just see if you understand everything, if not ask questions

You know, you can really only find \(|\cos x|\). You need more info to know the sign.

|dw:1436168642801:dw|

come*

that is from the hypotenuse

hypotenuse is the longest side of the triangle which was 3
cos x = adjacent / hypotenuse

\[
|\cos x| = \sqrt{1 - \sin^2 x}
\]

|dw:1436168854387:dw|

@UsukiDoll I am sorry :(

where hyp = 3 and adj = sqrt(8)

|dw:1436168916911:dw|

|dw:1436168957305:dw|

Haha

my spelling and grammar is on vacation xD oy!

The formula \[
\sin^2x+\cos^2x=1
\]Is based on the Pythagorean theorem.

He's not there yet wio lol

|dw:1436168987012:dw|

Yes

yes @Mindblast3r :D

so very true

|dw:1436169101210:dw|

problem is over nw party time ( ͡^ ͜ʖ ͡^)

|dw:1436169251275:dw|

Lol, I think usuki, Lyn, and qwerty should get a big thanks to :)

|dw:1436169321629:dw|

( ͡° ͜ʖ ͡°)

i met a man who said - "i have two daughters and both are girls."

|dw:1436169398594:dw|

ok people shows over, do something else.

Haha ok, bye :). And a way I go... |dw:1436169509148:dw|

lOL!

Now that's funny!