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MTALHAHASSAN2

  • one year ago

Use mathematical techniques to determine Fnet and acceleration for each of the following forces arrangements. For each, remember to include magnitude, unit, and direction

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  1. MTALHAHASSAN2
    • one year ago
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    |dw:1436166774039:dw|

  2. MTALHAHASSAN2
    • one year ago
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    how can we solve this type of problem can someone plz explain me

  3. anonymous
    • one year ago
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    \[ \sum F_y = 10N \sin (35^\circ) - 20N \\ \sum F_x = 10N \cos(35^\circ) \]\[ \mathbf F = \mathbf i \sum F_x + \mathbf j\sum F_y \]

  4. anonymous
    • one year ago
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    We could also say\[ \sum F_y = 10N\sin(35^\circ) +20N\sin(-90^\circ) \]Since \(\sin(-90^\circ) = -1\).

  5. IrishBoy123
    • one year ago
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    |dw:1436168731242:dw|

  6. MTALHAHASSAN2
    • one year ago
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    wait but how can we show that on the diagram

  7. MTALHAHASSAN2
    • one year ago
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    like how is it be -90

  8. MTALHAHASSAN2
    • one year ago
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    @wio

  9. MTALHAHASSAN2
    • one year ago
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    @inkyvoyd

  10. anonymous
    • one year ago
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    |dw:1436169653345:dw| angle with the \(x\) axis... clockwise angles are negative

  11. MTALHAHASSAN2
    • one year ago
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    oh ok thnx alot

  12. Michele_Laino
    • one year ago
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    we can write the subsequent vector equation: \[\Large {{\mathbf{F}}_{\mathbf{1}}} + {{\mathbf{F}}_{\mathbf{2}}} + M{\mathbf{g}} = M{\mathbf{a}}\] where a is the acceleration of our object, and M is its mass, furthermore g, is the earth gravity |dw:1436186357407:dw|

  13. Michele_Laino
    • one year ago
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    so we have the subsequent scalar equations: \[\Large \left\{ \begin{gathered} {F_1}\cos \theta = M{a_x} \hfill \\ \hfill \\ {F_1}\sin \theta - Mg - {F_2} = M{a_z} \hfill \\ \end{gathered} \right.\] where F_1 and F_2 are the magnitude of the corresponding vectors |dw:1436186583052:dw|

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