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MTALHAHASSAN2
 one year ago
Use mathematical techniques to determine Fnet and acceleration for each of the following forces arrangements. For each, remember to include magnitude, unit, and direction
MTALHAHASSAN2
 one year ago
Use mathematical techniques to determine Fnet and acceleration for each of the following forces arrangements. For each, remember to include magnitude, unit, and direction

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MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436166774039:dw

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0how can we solve this type of problem can someone plz explain me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[ \sum F_y = 10N \sin (35^\circ)  20N \\ \sum F_x = 10N \cos(35^\circ) \]\[ \mathbf F = \mathbf i \sum F_x + \mathbf j\sum F_y \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We could also say\[ \sum F_y = 10N\sin(35^\circ) +20N\sin(90^\circ) \]Since \(\sin(90^\circ) = 1\).

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436168731242:dw

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0wait but how can we show that on the diagram

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0like how is it be 90

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436169653345:dw angle with the \(x\) axis... clockwise angles are negative

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0we can write the subsequent vector equation: \[\Large {{\mathbf{F}}_{\mathbf{1}}} + {{\mathbf{F}}_{\mathbf{2}}} + M{\mathbf{g}} = M{\mathbf{a}}\] where a is the acceleration of our object, and M is its mass, furthermore g, is the earth gravity dw:1436186357407:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0so we have the subsequent scalar equations: \[\Large \left\{ \begin{gathered} {F_1}\cos \theta = M{a_x} \hfill \\ \hfill \\ {F_1}\sin \theta  Mg  {F_2} = M{a_z} \hfill \\ \end{gathered} \right.\] where F_1 and F_2 are the magnitude of the corresponding vectors dw:1436186583052:dw
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