## anonymous one year ago how do you determine the intercepts from an equation or graph???

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1. Owlcoffee

for the Y- intercept, you replace all the x's for zeroes, because any y-intercept has coordinates of (0,k) where "k" is a real number, for instance: $f:f(x)=e^x-u$ This function will have a Y-intercept of "1-k" because by definition, you fin the Y-intercept by replacing all the x's for zero, in other words "f(0)": $f: f(0)=e^0-u$ $f:f(0)=1-u$ So, we conclude that the function f intersects the y-axis on the point (0,1-u). For the x-interception it's a little more complex, but easy as well, because it's pretty much the opposite of the y-interception, the x-interception points are often called "roots" or "zeroes" of the function. So, by definition a root point must have coordinates (k,0) where "k" is a real number, let's take for example: $g:g(x)=3x-9$ In order to find the roots of this function we look for the values for "x" that make the whole function g equal zero, meaning "g(x)=0": $3x-9=0$ And we solve for "x": $x=\frac{ 9 }{ 3 }$ $x=3$ So, now we have found that the function g has it's x-interception on the coordinates (3,0).

2. anonymous

thank you so much :-)