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anonymous
 one year ago
If tan theta =12/5 and cos theta =5/13, then what is sin theta?
anonymous
 one year ago
If tan theta =12/5 and cos theta =5/13, then what is sin theta?

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: \[\tan \theta = \frac{{\sin \theta }}{{\cos \theta }}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino totally missed that. Much simpler than what I was going to do

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i go on from there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what @Michele_Laino has posted is an identity for tan. From here you plug in your numbers and solve for sin Θ

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1ok! please continue @peachpi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer i got is 12/13

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure what i did, is that correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you should have gotten a negative number

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1you're missing a negative sign.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would be 12/13???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just did the question again and got 5/13..... i am overthinking the problem i think

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer is 12/13

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436185957944:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(\theta)\cos(\theta) = \sin(\theta) \] since we are given 12/5 for tangent and 5/13 for cosine \[\frac{12}{5}(\frac{5}{13}) = \sin(\theta) \] the 5's cancel and you are left with 12/13

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1wow this is the first time I've done like this to be honest xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you guys!!!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0me too. I usually draw it and use the quadrants

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1same... since sin was negative and cos was negative, I'm assuming that we were in quadrant 3 because tangent is positive.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. I was dutifully drawing a picture when michele came in and blew my mind xD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1hmmm the triangle method would've worked too.. because tangent = opposite/adjacent = 12/5 and cosine = adjacent/hypotenuse = 5/13 dw:1436186175987:dw except we have to respect the fact that since cosine is negative we are placed in one of the four quadrants.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yeah I remember have those problems with the triangles like this and the textbook was like one of them is negative so which quadrant are we

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1sorry my typing not working tonight xD but quadrant three is 180 degrees270 degrees and only tangent is positive.
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