What is the approximate value of 0 , if tan 0 = 7/9 ? , 38° 52° 74° 16° 63°

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What is the approximate value of 0 , if tan 0 = 7/9 ? , 38° 52° 74° 16° 63°

Mathematics
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I need this explained I don't understand this
we can write this: \[\tan \left( {45} \right) = 1 = \frac{7}{9} + \frac{2}{9} = \tan \theta + \frac{2}{9}\]

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Other answers:

so, we have: \[\tan \theta = \tan \left( {45} \right) - \frac{2}{9}\] then we can state that \theta is less than 45 degrees
so could I sub one of the answers into the equation lets say Tan(38) what could I sub in for that?
yes! try with 38 degrees
so would 2/9 work still o should I use something different
or*
for current exercise, 2/9 works well, since: (2/9)+ (7/9)=1= tan(45)
furthermore, since: \[\tan 30 = \frac{{\sqrt 3 }}{3} > \frac{{1.7}}{3} = \frac{{5.1}}{9}\] our angle \thta has be greater than 30 degrees
ok
its bigger than 30 and less than 45 so which answer would work
so 38 would be the answer??
yes! That's right!
yes thank you so much
I gave you a medal

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