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BeastBoy17
 one year ago
What is the approximate value of 0 , if tan 0 = 7/9 ? ,
38°
52°
74°
16°
63°
BeastBoy17
 one year ago
What is the approximate value of 0 , if tan 0 = 7/9 ? , 38° 52° 74° 16° 63°

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BeastBoy17
 one year ago
Best ResponseYou've already chosen the best response.0I need this explained I don't understand this

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can write this: \[\tan \left( {45} \right) = 1 = \frac{7}{9} + \frac{2}{9} = \tan \theta + \frac{2}{9}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, we have: \[\tan \theta = \tan \left( {45} \right)  \frac{2}{9}\] then we can state that \theta is less than 45 degrees

BeastBoy17
 one year ago
Best ResponseYou've already chosen the best response.0so could I sub one of the answers into the equation lets say Tan(38) what could I sub in for that?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! try with 38 degrees

BeastBoy17
 one year ago
Best ResponseYou've already chosen the best response.0so would 2/9 work still o should I use something different

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1for current exercise, 2/9 works well, since: (2/9)+ (7/9)=1= tan(45)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1furthermore, since: \[\tan 30 = \frac{{\sqrt 3 }}{3} > \frac{{1.7}}{3} = \frac{{5.1}}{9}\] our angle \thta has be greater than 30 degrees

BeastBoy17
 one year ago
Best ResponseYou've already chosen the best response.0its bigger than 30 and less than 45 so which answer would work

BeastBoy17
 one year ago
Best ResponseYou've already chosen the best response.0so 38 would be the answer??

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! That's right!

BeastBoy17
 one year ago
Best ResponseYou've already chosen the best response.0yes thank you so much
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