## BeastBoy17 one year ago What is the approximate value of 0 , if tan 0 = 7/9 ? , 38° 52° 74° 16° 63°

1. BeastBoy17

@ganeshie8

2. BeastBoy17

I need this explained I don't understand this

3. Michele_Laino

we can write this: $\tan \left( {45} \right) = 1 = \frac{7}{9} + \frac{2}{9} = \tan \theta + \frac{2}{9}$

4. Michele_Laino

so, we have: $\tan \theta = \tan \left( {45} \right) - \frac{2}{9}$ then we can state that \theta is less than 45 degrees

5. BeastBoy17

so could I sub one of the answers into the equation lets say Tan(38) what could I sub in for that?

6. Michele_Laino

yes! try with 38 degrees

7. BeastBoy17

so would 2/9 work still o should I use something different

8. BeastBoy17

or*

9. Michele_Laino

for current exercise, 2/9 works well, since: (2/9)+ (7/9)=1= tan(45)

10. Michele_Laino

furthermore, since: $\tan 30 = \frac{{\sqrt 3 }}{3} > \frac{{1.7}}{3} = \frac{{5.1}}{9}$ our angle \thta has be greater than 30 degrees

11. BeastBoy17

ok

12. BeastBoy17

its bigger than 30 and less than 45 so which answer would work

13. BeastBoy17

so 38 would be the answer??

14. Michele_Laino

yes! That's right!

15. BeastBoy17

yes thank you so much

16. BeastBoy17

I gave you a medal

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