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BeastBoy17

  • one year ago

What is the approximate value of 0 , if tan 0 = 7/9 ? , 38° 52° 74° 16° 63°

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  1. BeastBoy17
    • one year ago
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    @ganeshie8

  2. BeastBoy17
    • one year ago
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    I need this explained I don't understand this

  3. Michele_Laino
    • one year ago
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    we can write this: \[\tan \left( {45} \right) = 1 = \frac{7}{9} + \frac{2}{9} = \tan \theta + \frac{2}{9}\]

  4. Michele_Laino
    • one year ago
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    so, we have: \[\tan \theta = \tan \left( {45} \right) - \frac{2}{9}\] then we can state that \theta is less than 45 degrees

  5. BeastBoy17
    • one year ago
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    so could I sub one of the answers into the equation lets say Tan(38) what could I sub in for that?

  6. Michele_Laino
    • one year ago
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    yes! try with 38 degrees

  7. BeastBoy17
    • one year ago
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    so would 2/9 work still o should I use something different

  8. BeastBoy17
    • one year ago
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    or*

  9. Michele_Laino
    • one year ago
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    for current exercise, 2/9 works well, since: (2/9)+ (7/9)=1= tan(45)

  10. Michele_Laino
    • one year ago
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    furthermore, since: \[\tan 30 = \frac{{\sqrt 3 }}{3} > \frac{{1.7}}{3} = \frac{{5.1}}{9}\] our angle \thta has be greater than 30 degrees

  11. BeastBoy17
    • one year ago
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    ok

  12. BeastBoy17
    • one year ago
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    its bigger than 30 and less than 45 so which answer would work

  13. BeastBoy17
    • one year ago
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    so 38 would be the answer??

  14. Michele_Laino
    • one year ago
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    yes! That's right!

  15. BeastBoy17
    • one year ago
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    yes thank you so much

  16. BeastBoy17
    • one year ago
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    I gave you a medal

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