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anonymous

  • one year ago

How do you solve this? The plan shows part of a roof on a house. A horizontal beam parallel to the base of the roof connects the roof and the central pillar. What is the unknown measurement on the plan? http://www.clipular.com/c/5193058980200448.png?k=w4SPOFD6juQAXGqjh1HwH8E9_zE

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  1. anonymous
    • one year ago
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    @peachpi

  2. anonymous
    • one year ago
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    @ganeshie8

  3. anonymous
    • one year ago
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    @aaronq

  4. anonymous
    • one year ago
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    @sleepyhead314

  5. anonymous
    • one year ago
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    Thank You so FLIPPING much

  6. sleepyhead314
    • one year ago
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    We are given two similar triangles :) One of the triangles has sides 14 and 8 the other triangle has sides (? + 14) and (8 + 15) do you see what I mean? :)

  7. sleepyhead314
    • one year ago
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    btw Welcome to OpenStudy ;) sorry that you weren't getting help fast enough .-.

  8. anonymous
    • one year ago
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    Do I have to subtract the 8 and the 5 to get the (?) And thanks, and its fine lol

  9. sleepyhead314
    • one year ago
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    One of the triangles has sides 14 and 8 the other triangle has sides (? + 14) and (8 + 15) With these two pieces of information, we can make a ratio thing 14 8 ------------- = --------------- (? + 14) (8 + 15)

  10. sleepyhead314
    • one year ago
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    sorry, gimma a sec, I'm not sure that was right

  11. anonymous
    • one year ago
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    Your good. At least your helping :)

  12. sleepyhead314
    • one year ago
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    it's right, there had been just another way to right it and I got confused xD so 14 8 ------------- = --------------- (? + 14) (8 + 15) can you cross multiply and solve for the "?" :)

  13. anonymous
    • one year ago
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    Woa, This is confusing. Sorry I'm a slowpoke. I'll figure it out. Thank you for your help :)

  14. sleepyhead314
    • one year ago
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    No worries ^_^ cross multiplying really is confusing at times :P (I finally figured it out like 3 years after I was supposed to have learned it xD) would you like for me to help break it down more for you? :)

  15. anonymous
    • one year ago
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    Haha. Thank you so much. Your very helpful and comforting. But yes that would be great

  16. sleepyhead314
    • one year ago
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    here's how I learned it Have you seen 1 --- x 2 = 1 2 happen before?

  17. anonymous
    • one year ago
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    Yeah I see it

  18. sleepyhead314
    • one year ago
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    it is the same idea :) 14 8 ------------- = --------------- (? + 14) (8 + 15) we would multiply both sides by (? + 14) first and get 14 8*(? + 14) ---------- = -------------- (1) (8 + 15) it would cancel out the Denominator on the Left side and stay in the Numerator on the Right side

  19. anonymous
    • one year ago
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    So for the earlier equation its 112 and 322?

  20. sleepyhead314
    • one year ago
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    you got it :) 322 = 8*? + 112

  21. anonymous
    • one year ago
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    So the answer to the question is that? ._.

  22. sleepyhead314
    • one year ago
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    not quite xD 322 = 8x + 112 let's use the variable "x"? does that look familiar? can you solve for "x"?

  23. anonymous
    • one year ago
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    x = 1 and 1 times 8 is 8?

  24. sleepyhead314
    • one year ago
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    hmm?

  25. sleepyhead314
    • one year ago
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    322 = 8x + 112 -112 -112 subtract 112 from both sides to get "8x" alone ------------------------- 210 = 8x

  26. anonymous
    • one year ago
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    Oh okay :D

  27. sleepyhead314
    • one year ago
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    then divide both sides by 8 to get "x" alone 210 = 8x ------ ---- 8 8

  28. anonymous
    • one year ago
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    26.25 and the 8 gets cancelled out?

  29. sleepyhead314
    • one year ago
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    exactly :)

  30. anonymous
    • one year ago
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    Wow :) Thank You so much. You tha realest dawg. Heres some DAP.... Boom!

  31. sleepyhead314
    • one year ago
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    I'm happy I could help :)

  32. anonymous
    • one year ago
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    Yes. When no-one else was there you woke up and showed me the way. Your my mathematical savior. Theres a special pace for people like you in heaven.

  33. sleepyhead314
    • one year ago
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    "woke up" punny considering my name xD lol

  34. sleepyhead314
    • one year ago
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    I will be on and off throughout the rest of the day, if you need any more help, just tag me ^_^

  35. anonymous
    • one year ago
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    Thank You sooooo much!

  36. anonymous
    • one year ago
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    Have a great day :)

  37. sleepyhead314
    • one year ago
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    you too :)

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