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ASAPT
 one year ago
Given that D is equidistant to G and F, find m<GED
A. 38 degrees
B. 40 degrees
C. 41 degrees
D. 45 degrees
ASAPT
 one year ago
Given that D is equidistant to G and F, find m<GED A. 38 degrees B. 40 degrees C. 41 degrees D. 45 degrees

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ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino @ganeshie8

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since the point D is equidistant from G and F, then the line ED is the bisector of the angle GEF, then we can write this: \[\Large 2x + 20 = 5x  10\] please solve for x

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1subtractin 2x from both sides, we get: \[\Large \begin{gathered} 2x + 20  2x = 5x  10  2x \hfill \\ \hfill \\ 20 = 3x  10 \hfill \\ \end{gathered} \] then adding 10 to both sides we get: \[\Large \begin{gathered} 20 + 10 = 3x + 10  10 \hfill \\ \hfill \\ 30 = 3x \hfill \\ \end{gathered} \] now divide both sides by 3, what do you get?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1ok! we have x=10 so the measure of the angle GED, is: (2*x+20)+(5*x10)=(2*10+20)+(5*1010)=...?

ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0that's a lot of numbers I don't have much time I have like 17 left and a time limit!!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: \[\begin{gathered} \left( {2x + 20} \right) + \left( {5x  10} \right) = \left( {2 \times 10 + 20} \right) + \left( {5 \times 10  10} \right) = ...? \hfill \\ = \left( {20 + 20} \right) + \left( {50  10} \right) = 40 + 40 = ...? \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1sorry, the angle GEF is 80 degrees, the measure of the angle GED is: \[2x + 20 = 2 \times 10 + 20 = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[2x + 20 = 2 \times 10 + 20 = 20 + 20 = ...?\]
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