anonymous
  • anonymous
In the following reaction, how many grams of lead(II) nitrate Pb(NO3)2 will produce 425 grams of sodium nitrate (NaNO3)? Pb(NO3)2(aq) + 2 NaBr(aq) PbBr2(s) + 2 NaNO3(aq) The molar mass of Pb(NO3)2 is 331.21 grams and that of NaNO3 is 85 grams. 828.03 grams 54.54 grams 218.14 grams 3312.10 grams 110.00 grams
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Cuanchi
  • Cuanchi
m1= 425 grams of sodium nitrate (NaNO3) m2= ? grams of lead(II) nitrate Pb(NO3)2 MM1= 85 grams of NaNO3 is MM2=molar mass of Pb(NO3)2 is 331.21 grams 1) convert the grams of sodium nitrate to moles of sodium nitrate ( n1=m1/MM1) n=moles: m1=mass of sodium nitrate; MM1= molecular mass of sodium nitrate. 2) according to the stoiquiometry of the reaction you can see that 1 mol of Pb(NO3)2 will produce 2 mol of NaNO3(aq). Then divide n1 by 2 to calculate the n2 or moles of Pb(NO3)2 that you will need. n2= n1/2 3) convert the moles of Pb(NO3)2 to grams with the same formula used in 1) but now isolate m. => m2= n2/MM2

Looking for something else?

Not the answer you are looking for? Search for more explanations.