anonymous
  • anonymous
Can someone help me? I will give a fan and a medal! Maria is making a stained glass window in the form of a kite. The width of the window must be 15 in., and she only has enough stained glass to cover 60 in squared. What should the height of the window be? A. 4 in. B. 6 in. C. 8 in. D. 12 in. https://media.education2020.com/evresources/2004-05-02-04-00_files/i0340001.jpg
Mathematics
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anonymous
  • anonymous
Can someone help me? I will give a fan and a medal! Maria is making a stained glass window in the form of a kite. The width of the window must be 15 in., and she only has enough stained glass to cover 60 in squared. What should the height of the window be? A. 4 in. B. 6 in. C. 8 in. D. 12 in. https://media.education2020.com/evresources/2004-05-02-04-00_files/i0340001.jpg
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
|dw:1436205097006:dw|
anonymous
  • anonymous
so we work backwards the formula for find the area of a kite is xy/2

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anonymous
  • anonymous
|dw:1436205250713:dw|
anonymous
  • anonymous
|dw:1436205275114:dw|
anonymous
  • anonymous
do you know what to do next?
anonymous
  • anonymous
Find x so that the equation is true?
anonymous
  • anonymous
yes! do you know how to get there?
anonymous
  • anonymous
would i do 60 times two and divide by 15
anonymous
  • anonymous
yep you got it!!
anonymous
  • anonymous
Thank you :)
anonymous
  • anonymous
no problem!

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