vera_ewing
  • vera_ewing
@Michele_Laino
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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vera_ewing
  • vera_ewing
Michele_Laino
  • Michele_Laino
applying the distrinutive property of multiplication over addition, we can write the se steps: \[\Large \begin{gathered} {\left( {\cos \theta } \right)^2}\left\{ {1 + {{\left( {\tan \theta } \right)}^2}} \right\} = \hfill \\ \hfill \\ = {\left( {\cos \theta } \right)^2} + {\left( {\cos \theta } \right)^2}{\left( {\tan \theta } \right)^2} = \hfill \\ \hfill \\ = {\left( {\cos \theta } \right)^2} + {\left( {\cos \theta } \right)^2}\frac{{{{\left( {\sin \theta } \right)}^2}}}{{{{\left( {\cos \theta } \right)}^2}}} \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
please continue

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vera_ewing
  • vera_ewing
-1 ?
Michele_Laino
  • Michele_Laino
hint: |dw:1436196847953:dw|
vera_ewing
  • vera_ewing
Oh so the answer must be A!
Michele_Laino
  • Michele_Laino
yes!
vera_ewing
  • vera_ewing
Oh wait I got it wrong :(
Michele_Laino
  • Michele_Laino
please keep in mind that: \[\Large \begin{gathered} {\left( {\cos \theta } \right)^2} + {\left( {\cos \theta } \right)^2}\frac{{{{\left( {\sin \theta } \right)}^2}}}{{{{\left( {\cos \theta } \right)}^2}}} = \hfill \\ \hfill \\ = {\left( {\cos \theta } \right)^2} + {\left( {\sin \theta } \right)^2} = 1 \hfill \\ \end{gathered} \]
vera_ewing
  • vera_ewing
Yep. That makes sense. Thanks Michele.
Michele_Laino
  • Michele_Laino
:)

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