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anonymous

  • one year ago

A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy? 2/9 3/9 4/9 5/9

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  1. Mehek14
    • one year ago
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    \(\dfrac{1}{9}+\dfrac{3}{9}\)

  2. Mehek14
    • one year ago
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    \(=\dfrac{4}{9}\\ \dfrac{9}{9}-\dfrac{4}{9}=answer\)

  3. Mehek14
    • one year ago
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    @amandacross ?

  4. anonymous
    • one year ago
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    sorry thank you so much! @Mehek14

  5. Mehek14
    • one year ago
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    yw \(\ddot\smile\)

  6. anonymous
    • one year ago
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    so the answer would be 5/9 correct? @Mehek14

  7. Mehek14
    • one year ago
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    yes

  8. anonymous
    • one year ago
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    ok thanks!

  9. anonymous
    • one year ago
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    can you help me with another problem that i am stuck on? @Mehek14

  10. Mehek14
    • one year ago
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    sure ut make another post

  11. Mehek14
    • one year ago
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    but*

  12. anonymous
    • one year ago
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    Jenny has some tiles in a bag. The tiles are of three different colors: purple, pink, and orange. Jenny randomly pulls a tile out of the bag, records the color, and replaces the tile in the bag. She does this 50 times. The results are recorded in the given table: color of tiles: purple,pink, orange. number of times tile is drawn: 4, 24, 22. What is the experimental probability that Jenny will pull out a pink tile?

  13. Mehek14
    • one year ago
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    do you have answer choices?

  14. anonymous
    • one year ago
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    22/50 22/28 24/50 4/50

  15. anonymous
    • one year ago
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    is it C??

  16. Mehek14
    • one year ago
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    from your table it says that pink was drawn 24 times from 50 so \(\dfrac{24}{50}\) experimental probability means the probability of something occurring from what was conducted so all you needed to do was look at the table

  17. anonymous
    • one year ago
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    ok?

  18. anonymous
    • one year ago
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    so its C?

  19. Mehek14
    • one year ago
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    yea

  20. anonymous
    • one year ago
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    thanks again!

  21. Mehek14
    • one year ago
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    yw

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