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anonymous
 one year ago
What is the simplified form of the quantity of x plus 7, all over the quantity of x plus 3 + the quantity of x minus 4, all over 3?
anonymous
 one year ago
What is the simplified form of the quantity of x plus 7, all over the quantity of x plus 3 + the quantity of x minus 4, all over 3?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436202319724:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @geerky42 @Michele_Laino

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: the least common multiple between x+3 and 3 is: \[3\left( {x + 3} \right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be x2++3x28/3(x+3)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so we can write this: \[\Large \begin{gathered} \frac{{x + 7}}{{x + 3}} + \frac{{x  4}}{3} = \hfill \\ \hfill \\ = \frac{{3\left( {x + 7} \right) + \left( {x + 3} \right)\left( {x  4} \right)}}{{3\left( {x + 3} \right)}} = ... \hfill \\ \end{gathered} \] please continue

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x+7)(x+3)(x4)/3(X+3)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2not exactly, since you have to compute the multiplications first

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2\[3\left( {x + 7} \right) = 3x + 3 \times 7 = 3x + 21\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large \left( {x + 3} \right)\left( {x  4} \right) = x \cdot x  4x + 3x  4 \cdot 3 = ...\] here, I have applied the foil procedure

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2please simplify, what do you get?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so the numerator is: \[\Large 3x + 21 + {x^2}  x  12 = ...\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2perfect! so your expression becomes: \[\Large \frac{{x + 7}}{{x + 3}} + \frac{{x  4}}{3} = \frac{{{x^2} + 2x + 9}}{{3\left( {x + 3} \right)}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh! Thankyou! I need one more please?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the simplified form of the quantity of x plus 9, all over the quantity of 2x plus 3 + the quantity of x plus 4, all over the quantity of x plus 2?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2please, make a drawing of your expression

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2here the least common multiple is: \[\left( {2x + 3} \right)\left( {x + 2} \right)\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! So we can write: \[\large \frac{{x + 9}}{{2x + 3}} + \frac{{x + 4}}{{x + 2}} = \frac{{\left( {x + 9} \right)\left( {x + 2} \right) + \left( {x + 4} \right)\left( {2x + 3} \right)}}{{\left( {2x + 3} \right)\left( {x + 2} \right)}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2now you have to apply the foil method in order to evaluate this: \[\Large \left( {x + 9} \right)\left( {x + 2} \right) = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! Now do the same with this expression: \[\Large {\left( {x + 4} \right)\left( {2x + 3} \right)}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! so the numerator is: \[\Large {x^2} + 11x + 18 + 2{x^2} + 11x + 12 = ...\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I got: 3 x^2+...

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large {3{x^2} + 22x + 30}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes bcuz 1x2+2x2=3x2. I forgot about the imaginary 1

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! So your original expression, becomes: \[\Large \frac{{x + 9}}{{2x + 3}} + \frac{{x + 4}}{{x + 2}} = \frac{{3{x^2} + 22x + 30}}{{\left( {2x + 3} \right)\left( {x + 2} \right)}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's not an answer choice, so I guess we will have to foil the bottom also

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! then what is: \[\Large \left( {2x + 3} \right)\left( {x + 2} \right) = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so we get: \[\Large \frac{{x + 9}}{{2x + 3}} + \frac{{x + 4}}{{x + 2}} = \frac{{3{x^2} + 22x + 30}}{{2{x^2} + 7x + 6}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! that's right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yay! Ok so I want you to keep helping me, and give u medals, so i AM going to close the question and ask another ok?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I'm sorry, I have to go to dinner :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:( Ok well thanks anyways!
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