anonymous
  • anonymous
Which of the following is a possible set of quantum numbers for an electron n, l, m subscript l, m subscript s ? A. (1, 1, 0, 1/2) B. (2, 1, 1, 1/2) C. (3, 2, 3, -1/2) D. (3, -2, 1, -1/2)
Chemistry
jamiebookeater
  • jamiebookeater
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vera_ewing
  • vera_ewing
Is this Apex chemistry?
anonymous
  • anonymous
no it's flvs
anonymous
  • anonymous
some pls help :/

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Photon336
  • Photon336
N = principle quantum number, tells you your energy level. L = shape that's the way I think of L m = can be less than or equal to L, shows how many orientations the orbitals can have. Can't be greater than L S = spin can either be +1/2 or -1/2 don't remember exactly. Say if we have 2P P orbitals have 3 possible orientations, Px,Py,Pz L = 1 M = +1 -1 0 corresponding to the Px,Py,Pz You can have spin up or down
Photon336
  • Photon336
If we have l = 2 That means we can have -2, -1, 0, 1, 2 which is five orientations Two electrons for each orbital so that's 10 total. That would give us a D orbital. a D orbital would have l = 2 and would start at principle quantum number of 3
Photon336
  • Photon336
You know that the spin can either be +1/2 or -1/2 so that won't tell you which one is right. So based off of what I said can you predict what the answer would be?

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