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anonymous
 one year ago
What is the equation of this circle in standard form?
(x − 5.5)squared + (y − 4)squared = 7
(x + 5.5)squared + (y + 4)squared = 3.5
(x − 5.5)squared + (y − 4)squared = 3.5
(x + 5.5)squared + (y + 4)squared = 12.25
(x − 5.5)squared + (y − 4)squared = 12.25
anonymous
 one year ago
What is the equation of this circle in standard form? (x − 5.5)squared + (y − 4)squared = 7 (x + 5.5)squared + (y + 4)squared = 3.5 (x − 5.5)squared + (y − 4)squared = 3.5 (x + 5.5)squared + (y + 4)squared = 12.25 (x − 5.5)squared + (y − 4)squared = 12.25

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436206108326:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is the center (2,4) and the point on the circle (9,4)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, (2,4) is also a point on the circle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the center doesn't have any coordinates

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, that makes more sense. So dw:1436206427235:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the diameter would be 7, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh wait yea, sorry i had a dumb moment

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, you can always fall back on the distance formula \[\large d=\sqrt{(x_{2}x_{1})^{2}+(y_{2}y_{1})^{2}}\]\[\large d=\sqrt{(92)^{2} + (44)^{2}}\]\[\large d=\sqrt{(7)^2}\]\[\large d=7\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But anyways, the diameter is 7, that means that the center of the circle is halfway between the x's of (2,4) and (9,4) right? Can you figure out what it is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@LegendarySadist hey sorry! something happened that it logged me out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey, I'm back. Openstudy update kicked me out too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got a little worried there lol i thought u weren't going to log back in

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyway, if we know the radius is 3.5, then just add 3.5 to 2 to get the x of the center point.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right, and the y is the same as both points.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now we have all the info we need. All that's left is to put it into standard form. \[\large (xh)^{2}~+~(yk)^{2}=r^{2}\] \[\large (h,k)~=~Center~coordinates~of~circle\] \[\large r~=~radius\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i hate this part like what is k supposed to be!?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large (h,k) = (x,y)\\\large h=x \\\large k=y\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait but the y is what?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(h,k) is the (x,y) of the center coordinates. The k is the y of the center.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but what number does k stand for? lol im sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's the same y as the other 2 points, so 4.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Almost \[\large r^{2}\] not \[\large 2r\] So \[\large 3.5^{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it's either D or E

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you sooo much!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]
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