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anonymous

  • one year ago

For the quantum number lower case L = 0, how many possible values are there for the quantum number m subscrip l? A. 0 B. 1 C. 2 D. 3

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  1. anonymous
    • one year ago
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    pls help

  2. thadyoung
    • one year ago
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    if \(l\) = 0 that means that your principle quantum number, \(n\)= 1 because \(l\) = \(n\) -1 and \(m\) can be any value from -\(l\) to +\(l\) So if i have: \(l\)= 2 \(m\) can be -2, -1, 0, +1, and +2 it's in that range!

  3. anonymous
    • one year ago
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    thank you!!

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