## tw101 one year ago Geometry problem that im a bit confused on. Using the law of sines, in triangle ABC, if m<B=105 degrees, b=23, a=14, find m<A

1. tw101

@ganeshie8

2. anonymous

So |dw:1436208788719:dw|

3. tw101

okay, what would I do next? i know the law of sines is Sin A/a=SinB/b=SinC/c, but when i substitute it all together it doesnt make sense to me.

4. anonymous

Just use the Law of sines ratio $\large \frac{sin(105)}{23}~=~\frac{sin<a}{14}$ Get <a alone

5. tw101

okay so would I do the inverse of sin and multiply both sides by 14?

6. anonymous

Well let's do it one step at a time. First is to yes, multiply both sides by 14. Tell me what you get.

7. tw101

sin (1470)/322

8. anonymous

It should look more like $\large \frac{14 \times sin(105)}{23}$

9. tw101

oh okay. and then do I inverse both sides?

10. anonymous

Correct

11. anonymous

So $\large <a~=~ asin \large( \normalsize \frac{14 \times sin(105)}{23} \large )$

12. tw101

okay i got 36.01

13. anonymous

That would be your answer :) good job

14. tw101

thank you so much!

15. anonymous

$\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile$

16. tw101

can i ask one more question?