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tw101
 one year ago
Geometry problem that im a bit confused on. Using the law of sines, in triangle ABC, if m<B=105 degrees, b=23, a=14, find m<A
tw101
 one year ago
Geometry problem that im a bit confused on. Using the law of sines, in triangle ABC, if m<B=105 degrees, b=23, a=14, find m<A

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So dw:1436208788719:dw

tw101
 one year ago
Best ResponseYou've already chosen the best response.0okay, what would I do next? i know the law of sines is Sin A/a=SinB/b=SinC/c, but when i substitute it all together it doesnt make sense to me.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just use the Law of sines ratio \[\large \frac{sin(105)}{23}~=~\frac{sin<a}{14}\] Get <a alone

tw101
 one year ago
Best ResponseYou've already chosen the best response.0okay so would I do the inverse of sin and multiply both sides by 14?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well let's do it one step at a time. First is to yes, multiply both sides by 14. Tell me what you get.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It should look more like \[\large \frac{14 \times sin(105)}{23}\]

tw101
 one year ago
Best ResponseYou've already chosen the best response.0oh okay. and then do I inverse both sides?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So \[\large <a~=~ asin \large( \normalsize \frac{14 \times sin(105)}{23} \large )\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That would be your answer :) good job

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]

tw101
 one year ago
Best ResponseYou've already chosen the best response.0can i ask one more question?
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