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tw101

  • one year ago

Geometry problem that im a bit confused on. Using the law of sines, in triangle ABC, if m<B=105 degrees, b=23, a=14, find m<A

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  1. tw101
    • one year ago
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    @ganeshie8

  2. anonymous
    • one year ago
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    So |dw:1436208788719:dw|

  3. tw101
    • one year ago
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    okay, what would I do next? i know the law of sines is Sin A/a=SinB/b=SinC/c, but when i substitute it all together it doesnt make sense to me.

  4. anonymous
    • one year ago
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    Just use the Law of sines ratio \[\large \frac{sin(105)}{23}~=~\frac{sin<a}{14}\] Get <a alone

  5. tw101
    • one year ago
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    okay so would I do the inverse of sin and multiply both sides by 14?

  6. anonymous
    • one year ago
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    Well let's do it one step at a time. First is to yes, multiply both sides by 14. Tell me what you get.

  7. tw101
    • one year ago
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    sin (1470)/322

  8. anonymous
    • one year ago
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    It should look more like \[\large \frac{14 \times sin(105)}{23}\]

  9. tw101
    • one year ago
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    oh okay. and then do I inverse both sides?

  10. anonymous
    • one year ago
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    Correct

  11. anonymous
    • one year ago
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    So \[\large <a~=~ asin \large( \normalsize \frac{14 \times sin(105)}{23} \large )\]

  12. tw101
    • one year ago
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    okay i got 36.01

  13. anonymous
    • one year ago
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    That would be your answer :) good job

  14. tw101
    • one year ago
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    thank you so much!

  15. anonymous
    • one year ago
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    \[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]

  16. tw101
    • one year ago
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    can i ask one more question?

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