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anonymous
 one year ago
What is the standard form of the equation of a circle that has its center at (2, 3) and passes through the point (2, 0)?
(x + 2)squared + (y + 3)squared = 9
(x − 2)squared + (y − 3)squared = 16
(x − 2)squared + (y − 3)squared = 4
(x + 2)squared + (y + 3)squared = 16
(x − 2)squared + (y + 3)squared = 9
anonymous
 one year ago
What is the standard form of the equation of a circle that has its center at (2, 3) and passes through the point (2, 0)? (x + 2)squared + (y + 3)squared = 9 (x − 2)squared + (y − 3)squared = 16 (x − 2)squared + (y − 3)squared = 4 (x + 2)squared + (y + 3)squared = 16 (x − 2)squared + (y + 3)squared = 9

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(2,3) and (2,0) have the same x. So 0(3)=?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So there's your radius. Now just put the info into standard form. \[\large (xh)^{2}~+~(yk)^{2}=r^{2}\] \[\large (h,k)~=~Center~coordinates~of~circle\] \[\large r~=~radius\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0either A or E right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right, A. And \[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]
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