vera_ewing
  • vera_ewing
At equilibrium, the concentration of calcium ions in a calcium chromate (CaCrO4) solution is 1 x 10^–4 mol/L at 25°C. In the same solution, the concentration of chromate ions is also 1 x 10^–4 mol/L. What is the Ksp of calcium chromate? Show your work.
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
vera_ewing
  • vera_ewing
@aaronq Please help!
welshfella
  • welshfella
sorry I've forgotten this stuff
aaronq
  • aaronq
Write the dissociation, then it's corresponding equilibrium equation (which is the Ksp equation). Plug in your values and solve

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

vera_ewing
  • vera_ewing
What's the dissociation and corresponding equilibrium equation?
aaronq
  • aaronq
the dissociation of CaCrO4 (in water)
aaronq
  • aaronq
and by that i mean a chemical equation
vera_ewing
  • vera_ewing
Okay, so what does the chemical equation look like? Can you set it up and then I solve?
aaronq
  • aaronq
nah, you have to try it
vera_ewing
  • vera_ewing
I don't know how :( Can you maybe explain it?
aaronq
  • aaronq
CaCrO4 is an ionic compound, right? what ions make up CaCrO4?
vera_ewing
  • vera_ewing
Not sure. It's covalent and ionic though, right?
aaronq
  • aaronq
it's ionic only. You should be able to identify the ions here, if you can't look the compound up on wikipedia and read a little about it
welshfella
  • welshfella
what i do remember is that Ca CrO4 disassociates in water to [Ca++] and [Cr2O4 --]
welshfella
  • welshfella
and sp means solubility product so i guess Ksp is the product of Ca++ ions and CrO4-- ions
vera_ewing
  • vera_ewing
Yep, I figured it out :) thanks
welshfella
  • welshfella
so that 10-4 8 10^-4 = 10^-8
welshfella
  • welshfella
oh Ok wd
Photon336
  • Photon336
CaCrO4 ----> Ca^2+ + CrO4^2- Ksp = [Ca^2+][CrO4^2-] Ksp = [x][x] Ksp = concentration of ions dissolved, like any K it's an equilibrium value, and it is temperature dependent. I'm assuming that the equilibrium is already reached and that the solution is saturated. B.c from my understanding that's what Ksp is. (Qsp = Ksp) Their concentrations are equal for both ions in the problem. So I think it's (1x10^-4)(1x10^-4) = Ksp. 10^-8

Looking for something else?

Not the answer you are looking for? Search for more explanations.