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Aizhalee

  • one year ago

Can I have help please with slopes . using the slope intercept format, we can plug in what we know for our new line. y =mx+b 5 = -2(4) + b, solve for 'b' then re write the equation with only the m and b terms with numbers.

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  1. anonymous
    • one year ago
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    Hi, so are you looking solve for b. I don''t understand what you mean by the other part. 5=-8+b, add 8 to both sides which cancels out the -8. b=13|dw:1436215552731:dw|

  2. aizhalee
    • one year ago
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    Thank you so much for your help, I appreciate it , I totally understand it now :)

  3. anonymous
    • one year ago
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    The other part is just to set that y and x back to normal. So \[\large y=mx+b\\\large y=-2x+13\]

  4. anonymous
    • one year ago
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    Alright glad to help

  5. anonymous
    • one year ago
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    y = -2x+13

  6. aizhalee
    • one year ago
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    @hafsa23 can you please help me with one so I can understand it please

  7. anonymous
    • one year ago
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    Yes

  8. aizhalee
    • one year ago
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    The equation of line WX is y = −2x − 5. Write an equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2).

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  9. aizhalee
    • one year ago
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    Can I have help with this please, I do not understand it at all . Thank you

  10. anonymous
    • one year ago
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    Alright, so perpendicular means that the slope will be a negative reciprocal

  11. anonymous
    • one year ago
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    \[Perpendicular line slope=1/2x\]

  12. aizhalee
    • one year ago
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    thats all ?

  13. anonymous
    • one year ago
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    Now using x and y from (-1, -2) to find b

  14. anonymous
    • one year ago
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    |dw:1436216196970:dw|\[y=1/2x-1.5\]

  15. anonymous
    • one year ago
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    here's a better drawing|dw:1436216291146:dw|

  16. anonymous
    • one year ago
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    does that help?

  17. aizhalee
    • one year ago
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    Yes but what letter is it ? A,B,C, or D ? what is the answer

  18. anonymous
    • one year ago
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    C, \[y=1/2x-3/2\]

  19. aizhalee
    • one year ago
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    Thank you

  20. anonymous
    • one year ago
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    You're welcome

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