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draw it out, please

|dw:1436218798400:dw|

The answer is correct, but that is the washer method.

oh, shell method!! ooooooooook

:)

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Got it

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the shape is like this
i have some good drawing skills don't yo think hahah

|dw:1436222936259:dw|

Thank you though

you integrated with respect to x yes?

dy

hmm why? the height of the cylinder goes in x direction

correct this is the shell method

the shell method is the cylinder method
can you show your work, how you integrated with dy

\[\int\limits_{1}^{4}2\pi(4-y)(\sqrt{y}-(y-2)dy +\int\limits_{0}^{1}2\pi(4-y)(2\sqrt{y})dy\]

let me draw that nicely with a program! this drawing confuses me lol

why do you have 0 to 1?

sorry can't focus, i will check this later :)

its correct the correct answer is 108pi/5

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\[y=x+2 \\ x=y-2 \\ \text{ and } y=x^2 \\ \text{ gives } x=\sqrt{y} \text{ or } x=-\sqrt{y}\]

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we have two difference things to look at because the left function switches at y=1

we've gone through I'd like to close

you can close it
just trying to help anyone who is still trying to understand it

Clicking on close and nothing is happening. Continue on if you want