## anonymous one year ago Simplify quantity 18 x minus 6 over 9 x to the fifth power all over quantity 15 x plus 5 over 21 x squared.

1. anonymous

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2. anonymous

3. Loser66

$\huge \dfrac{\frac{18x-6}{9x^5}}{\frac{15x+5}{21x^2}}$ Right?

4. anonymous

yeah!

5. Loser66

Do you know?? $\dfrac{{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}*\dfrac{d}{c}$

6. anonymous

No, i didn't know.

7. anonymous

as my answer, i got 14/5x^3 yes?

8. Loser66

Now, you know, just apply it into your expression, where a=18x-6 b= 9x^5 c= 15x+5 d= 21x^2 BTW, your answer is NOT correct

9. anonymous

oh:( Okay.

10. mathstudent55

Read 1. first, then 2. |dw:1436219545640:dw|

11. mathstudent55

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12. mathstudent55

Now factor each expression and cancel equal terms.

13. anonymous

ok so would the answer be 14(3x-1)/5x^3(3x+1)

14. anonymous

@mathstudent55

15. anonymous

@Loser66

16. anonymous

@phi @pooja195

17. anonymous

@Keigh2015 @KryoWolf @KakeFace @hba @hotguy

18. anonymous

@gold.shosho @gold.shosho

19. anonymous

sorry, Cream, this isnt my good zone in math

20. Keigh2015

I am not that good at math sorry this is not my zone

21. mathstudent55

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22. mathstudent55

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23. mathstudent55

You are correct.