anonymous
  • anonymous
What are the zero(s) of the function f(x) = the quantity of 5 x squared minus 25 x, all over x?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
@xapproachesinfinity
campbell_st
  • campbell_st
\[\frac{5x^2 - 25x}{x}\] what common factor do you see..?

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anonymous
  • anonymous
5x
campbell_st
  • campbell_st
ok... so I'll do that \[\frac{5x(x - 5)}{x}\] what common factor do you see in the numerator and denominator..?
anonymous
  • anonymous
x
campbell_st
  • campbell_st
ok so that leaves 5(x -5) = 0 so what value of x makes the equation true..?
anonymous
  • anonymous
5, 0
campbell_st
  • campbell_st
only 5 and when x = 0 in the original equation you have a zero denominator, which is undefined so at x = 0 you have a point of discontinuity... so the solution is x = 5 which comes from the simplified version of the original equation. hope it makes sense.
anonymous
  • anonymous
It does! Thank-you:)

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