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anonymous one year ago What are the zero(s) of the function f(x) = the quantity of 5 x squared minus 25 x, all over x?

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1. anonymous

@mathstudent55

2. anonymous

@xapproachesinfinity

3. campbell_st

$\frac{5x^2 - 25x}{x}$ what common factor do you see..?

4. anonymous

5x

5. campbell_st

ok... so I'll do that $\frac{5x(x - 5)}{x}$ what common factor do you see in the numerator and denominator..?

6. anonymous

x

7. campbell_st

ok so that leaves 5(x -5) = 0 so what value of x makes the equation true..?

8. anonymous

5, 0

9. campbell_st

only 5 and when x = 0 in the original equation you have a zero denominator, which is undefined so at x = 0 you have a point of discontinuity... so the solution is x = 5 which comes from the simplified version of the original equation. hope it makes sense.

10. anonymous

It does! Thank-you:)

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